To accept two numbers from the user; Display all prime numbers between these two numbers.
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To accept two numbers from the user; Display all prime numbers between these two numbers.
To accept two numbers from the user and display perfect numbers between these two numbers.
To accept two numbers from the user and display Armstrong number between these numbers.
Simple coding using DoWhile, IfElse
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その他の回答 (2 件)
B.k Sumedha
2015 年 5 月 28 日
Try this for Armstrong number:
clear, clc
% Let i take two numbers say 100 to 999
for i = 100 : 999
% We examine every digit in i
is = num2str(i);
% i1 is the left-most digit in i
i1 = str2num(is(1));
% i2 is the middle digit
i2 = str2num(is(2));
% i3 is the right-most digit in i
i3 = str2num(is(3));
% We calculate the probable AN
an = i1^3 + i2^3 + i3^3;
% We compare to the number itself
if i == an
% We display the pair of equal numbers
disp([i an])
end
end
B.k Sumedha
2015 年 5 月 28 日
This is for perfect numbers where u can change the values of m and n where they are the two input numbers
n=100;
m=10;
output = zeros(1,n);
for i = m:n
test = 1:i-1;
if (sum(test(mod(i,test) == 0)) == i)
output(i) = i;
end
end
output(output == 0) = []
3 件のコメント
B.k Sumedha
2015 年 5 月 28 日
Did u try with these two?
BeTrayer EK
2015 年 5 月 28 日
BeTrayer EK
2015 年 5 月 28 日
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