Graceful exit from a parfor loop
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If I detect an error while processing data within a parfor loop, I would like to gracefully exit the program. Can I delete the parallel pool object using "delete" to shut down all of the workers before exiting?
回答 (1 件)
Matt J
約14時間 前
1 投票
4 件のコメント
Clay Fulcher
20分 前
編集済み: Clay Fulcher
19分 前
Matt J
約2時間 前
Do you know if simply deleting the parallel pool object will accomplish the destruction of the tasks being performed by all the independent workers in the parfor loop?
A simple error will do that. If even one of the workers hits an error, the whole loop aborts and all of the workers stop what they are doing. The only question at that point is whether you want the pool left open. So your code could look like this:
function output=runSomething(poolSize)
objPool = parpool(poolSize);
objCleanup=onCleanup( @() delete(objPool));
try
parfor i=1:N
end
output=...
catch
disp 'The loop failed. Aborting'
output=[];
return
end
end
This will completely close the pool whether the function runs to successful completion or not.
A simple error will do that
Here's a demo of that. When worker #3 aborts with an error, you can see that all the other workers whose task is too long never complete it --
parpool(6)
runThis(0) %Short task. All workers except #3 complete
Worker 4 Completed
Worker 6 Completed
Worker 1 Completed
Worker 2 Completed
Worker 5 Completed
Error using test>runThis (line 11)
Worker 3 failed
runThis(30) %Only workers 4,5,6 complete
Worker 4 Completed
Worker 6 Completed
Worker 5 Completed
Error using test>runThis (line 11)
Worker 3 failed
function runThis(N)
t=[ N,N,0,0,0,0];
parfor i=1:6
if i~=3
pause(t(i))
disp("Worker " +i+" Completed")
else
error 'Worker 3 failed'
end
end
end
--
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