Matrix with Bell Triangle

2 ビュー (過去 30 日間)
Millone
Millone 2015 年 5 月 22 日
コメント済み: Millone 2015 年 5 月 22 日
I need to reshape a portion of a matrix computed with the values of a bell triangle where n is the number of rows of a matrix. How can I generate a matrix contain the bell values? I mean, as an example, for n= 4 but could be any value:
1
1 2
2 3 5
5 7 10 15
empty space with 0.
  6 件のコメント
Millone
Millone 2015 年 5 月 22 日
No, I have no tried it but I give it a test. Thanks
Millone
Millone 2015 年 5 月 22 日
I do not get it! I am just approaching Matlab!

サインインしてコメントする。

採用された回答

John D'Errico
John D'Errico 2015 年 5 月 22 日
Simple. Just use loops.
n = 5;
BellTri = zeros(n);
BellTri(1,1) = 1;
for i = 2:n
BellTri(i,1) = BellTri(i-1,i-1);
for j = 2:i
BellTri(i,j) = BellTri(i - 1,j-1) + BellTri(i,j-1);
end
end
BellTri
BellTri =
1 0 0 0 0
1 2 0 0 0
2 3 5 0 0
5 7 10 15 0
15 20 27 37 52

その他の回答 (3 件)

Titus Edelhofer
Titus Edelhofer 2015 年 5 月 22 日
O.k., when there is a full solution, I'm happy to share mine as well ;-)
function B = bell(n)
B = zeros(n);
B(1,1) = 1;
for row=2:n
B(row, 1:row) = B(row-1,row-1) + cumsum([0 B(row-1, 1:row-1)]);
end
Titus

Andrei Bobrov
Andrei Bobrov 2015 年 5 月 22 日
n = 5;
a = zeros(n);
a(1) = 1;
for jj = 1:n-1
a(jj+1,1:jj+1) = cumsum(a(jj,[jj,1:jj]),2);
end

Guillaume
Guillaume 2015 年 5 月 22 日
Assuming you're talking about this, I've tried to come up with a clever way to generate it, but didn't find any (didn't spend too much time on it either). When all else fail, loops always work:
bell = zeros(n);
bell(1) = 1;
for row = 2 : n
bell(row, 1) = bell(row-1, row-1);
for col = 2 : row
bell(row, col) = bell(row, col-1) + bell(row-1, col-1);
end
end

カテゴリ

Help Center および File ExchangeMatrix Indexing についてさらに検索

製品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by