How to find the approximation of the solution to an equation with an infinite series?

Hi, I am very new to matlab and I am trying to solve an equation with an infinite serie. The equation looks like this:

The variable is De and the rest are all parameters (R is 25e-06, the function is equal to 0.4764) I would really appreciate it if someone can give me a hint about how to do this. (Even better if you can provide a code sample). Thank you very much.

[Torsten]

What is the value of t ?

[John D'Errico]

Answers is not a service where we will write yor code for you. Just use a loop. Stop when the terms get small enough that it has converged to your satisfaction. MAKE AN EFFORT. If you wrrite some code, and THEN have a problem, ask your question then, showing you have made an effort. Ank how to fix what you did, and then you might get help.

[Kiet]

i am incredibly sorry sir, i kinda new to matlab and i don't know where to start, i will tried my best to solve the problems. Thanks for the advice sir!

[Sam Chak]

@Kiet

One very important mathematical clue!

syms n

%% Compute the infinite sum from n = 1 to infinity (uncountable noun)
f   = 1/n^2

f = 

S   = symsum(f, n, 1, Inf)

S = 

So, when , what do you get?

[Torsten]

@Sam Chak

Yes, this holds for t -> Inf.

[Sam Chak]

Hi @Torsten,

I was encouraging @Kiet to use symsum if he is unfamiliar with loops, as in some pure math programs, the professors do not teach the iterative control flow structures used in executing most mathematical expressions.

Anyhow, that solution only holds if t approaches 0 for . Moreover, with the quadratic terms and in the numerator, and the denominator has a relatively small value, the exponential decay function probably approaches 0, depending on the true values of and t.