フィルターのクリア

how can plot such a signal s(-t-5)?

1 回表示 (過去 30 日間)
sH
sH 2015 年 5 月 20 日
コメント済み: sH 2015 年 5 月 20 日
can anyone help me to make such a signal s(-t-5) from signal s? I have tried the following code: fliplr([zeros(1,5) s]) Is it right?

採用された回答

Abhiram Bhanuprakash
Abhiram Bhanuprakash 2015 年 5 月 20 日
Hi sH,
I think your approach is right, and it accounts for the Y axis values.
But, for the X axis indices, I think you should do something like this:
Say you have a signal s(n) = [1 2 3 4], and you wish to obtain s1(n) = s(-n-5):
s = [1 2 3 4];
inds = 0:length(s)-1;
figure, plot(inds,s); %considering time index 0 as the origin
s1 = fliplr([zeros(1,5) a]);
flippedInds = -(length(s1)-1):0;
figure, plot(flippedInds,s1);
For discrete signal plots, you can use the stem function instead of plot.
Hope this helps,
Cheers!
Abhiram.
  3 件のコメント
Abhiram Bhanuprakash
Abhiram Bhanuprakash 2015 年 5 月 20 日
Oops, sorry, my mistake.
It should be
s1 = fliplr([zeros(1,5) s]);
Thanks Walter for pointing it out.
sH
sH 2015 年 5 月 20 日
thanks everyone

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeGraphics Performance についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by