Plotting around zero deg. Angle
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I'm plotting an image using: Imagsc(x,y,C) where x is an angle vector from 280 deg to 50 deg trough 0 deg. I Want to see the image with zero at the center. Instead i have the data from 50 to 280. How to overcome this? The image looks like two halfs apart???
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回答 (3 件)
Star Strider
2025 年 2 月 17 日 19:39
Aside from not having any image to work with, I am not certain what you want.
First use plot to see what the problem may be.
Try this —
a = [280 0 50];
x = cosd(a);
y = sind(a);
figure
plot([x; zeros(size(x))], [y; zeros(size(y))])
axis('equal')
How do you intend to plot that as an image?
If this is not what you want, what about it needs to change?
.
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Star Strider
2025 年 2 月 17 日 20:22
Walter Roberson
2025 年 2 月 17 日 21:12
If the marginal x vector is [280...359, 0..50] then scatter3 will drawn the data in two sections, one from 0 to 50 and the other from 280 to 359. surf() and pcolor() will draw the data from 0 to 50 and then interpolate a large cell from 50 to 280, and then draw 280 to 359.
There are always options such as putting two adjacent axes side by side, one from 280 to 360 and the other from 0 to 50
Walter Roberson
2025 年 2 月 17 日 20:14
When you specify a vector for x for imagesc, MATLAB ignores everything except for the first and last entries. It does not care that your vector rises from 280 through 359 and then starts from 0 up to 50: it treats it as 280 down to 50 (with no zero passed through)
What you can do is set the x component to be -80 to 50, and then use xlabel() to change the labeling to [280 to 359, 0 to 50].
You might want to accompany that with a datacursormode configuration that has a function that adjusts the displayed x coordinate
mask = x < 0;
adjustx = x;
adjustx(mask) = 360+adjustx(mask);
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