trying to use the command hinfsyn on a rotary inverted pendulum for stabilization analysis
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Hello
I am trying to follow this paper
I have made following code for making the system looking like this

The code is given below
A=[0 0 1 0;
0 0 0 1;
0 39.32 -14.52 0;
0 81.78 -13.98 0;];
B=[0;0;25.54;24.59];
C=[1 0 0 0;
0 1 0 0];
D=[0;0;];
sys=ss(A,B,C,D);
sys.InputName={'u'};
sys.OutputName={'theta','alpha'};
s=tf('s');
Wact=0.002*(s+0.01)/(s+10);
Wact.u='u'; Wact.y='e1';
Wn1=ss(0.05);
Wn1.u='d1'; Wn1.y='wn1';
Wn2=ss(0.0275);
Wn2.u='d2'; Wn2.y='wn2';
Wx1=151.5/(s+50.5);
Wx1.u='theta'; Wx1.y='e2';
Wx2=202/(s+50.5);
Wx2.u='alpha'; Wx2.y='e3';
sdmeas=sumblk('y1 = theta+wn1');
abmeas=sumblk('y2 = alpha+wn2');
ICinputs={'d1','d2','u'};
ICoutputs={'e1','e2','e3','y1','y2'};
qsys=connect(sys,Wact,Wn1,Wn2,Wx1,Wx2,sdmeas,abmeas,ICinputs,ICoutputs);
When I am running the command hinfsyn I get following gamma
[~,~,gamma]=hinfsyn(qsys,2,1)
while in the paper they have
gamma=0.6951 in section 3.1 H-infinty controll. Where is my mistake or any solution to get the same answer as in the paper ?
Thanks for all answers
Tor Erik Haavik
3 件のコメント
Paul
2025 年 1 月 19 日
編集済み: Paul
2025 年 1 月 19 日
Based on the article, it's hard to say what is "correct" because the results from the article are not able to be replicated, at least for me. Every time I look at a different section I have more concerns. I'm really curious about how the authors developed Figure 6.
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