There is any function displacement

This array
I want find differential between the numbers then, i want find displacement
and thank u

回答 (1 件)

Joseph Cheng
Joseph Cheng 2015 年 5 月 17 日
編集済み: Joseph Cheng 2015 年 5 月 17 日

0 投票

you can use the function diff() to perform this differential. so you'll have something like
da = diff(a); %this will get your your [4 5 ...]
then you can perform your da./a(1:end-1)*100.

7 件のコメント

abduall hassn
abduall hassn 2015 年 5 月 17 日
編集済み: abduall hassn 2015 年 5 月 17 日
yes brother but this da/a(1:end-1)*100. not given correct ans
Joseph Cheng
Joseph Cheng 2015 年 5 月 17 日
編集済み: Joseph Cheng 2015 年 5 月 17 日
well then you did not explain it very well. this will give you the displacement that you asked for of each neighboring indexes, so by going diff(a) you get your first second third differential like you explained. Then you can divide by the original and multiply by the 100.
so if
da = 100*diff(a)./a(1:end-1)
is not what you are looking for please explain more
abduall hassn
abduall hassn 2015 年 5 月 17 日
thank u brother now is ok
abduall hassn
abduall hassn 2015 年 5 月 17 日
i used this data a=[1616400 1749524 23755514 160257 13653988 935134 15192144] i have done same u said bu i got problem step 1 da=diff(a) step2 da = 100*diff(a)./a(1:end-1)
da =
1.0e+003 * this is problem i dnt like to come because it change the ans
ans 0.0082 1.2578 -0.0993 8.4201 -0.0932 1.5246
i want remove this 1.0e+003 because change ans
Image Analyst
Image Analyst 2015 年 5 月 17 日
Try executing this line of code before you do that:
format long g;
abduall hassn
abduall hassn 2015 年 5 月 19 日
Brother if i have array more than one rows and columns like [ 56 78 6 88 67 77 64 93 60 70 22 34 29 45 15] How we can do it thank you and thank you
Joseph Cheng
Joseph Cheng 2015 年 5 月 19 日
da = diff(a,[],2)./a read the documentation of the function diff() to see that by performing diff(a,[],2) we perform it in the correct dimension.

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