Cell Array storing RGB

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SG
SG 2015 年 5 月 15 日
コメント済み: SG 2015 年 5 月 15 日
I am storing color short names in a cell array as follows:
color{i,j} = 'r';
Then I'd like to use this cell array to set the color properties of some texts as follows:
text('String', d{i,j},'Units', 'Points',...
'FontSize', 8, 'HorizontalAlignment', 'right', ...
'Color', color(i,j));
However, I get the error "Color value must be a 3 element numeric vector". I have tried using a function that convert the short name of colors to their RGB triplet, but it seems that color(i,j) does not output a string/char. How should I go about this? Thank you.

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Walter Roberson
Walter Roberson 2015 年 5 月 15 日
If you are doing one at a time, then color{i,j} gets to the character.
If you were trying to do a whole bunch of them, such as to name the colors for each point of scatter3, then a lookup table is probably easiest.
RGBtab = [0 0 1; 0 1 0; 0 0 0; 1 0 0]; %RGB codes for colors
colorabbr = {'b', 'g', 'k', 'r'}; %must match order of RGB triple rows
[tf, idx] = ismember(color(:), colorabbr); %look up codes to find index
colorrgb = RGBtab(idx,:); %convert to RGB triples
and now colorrgb would be an N x 3 of RGB. If you needed to you could
reshape(colorrgb, size(color,1), size(color,2), 3)
to get a truecolor array
  1 件のコメント
SG
SG 2015 年 5 月 15 日
Wow that works perfectly. Thank you.

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その他の回答 (1 件)

Image Analyst
Image Analyst 2015 年 5 月 15 日
That should work except that you used parentheses which gives the whole cell, rather than braces, which gives the contents of the cell.
color(i,j) = a cell, the cell in the ith row, jth column of the cell array called color.
color{i,j} = the CONTENTS OF the cell at row i, column j
Try this:
text('String', d{i,j},'Units', 'Points',...
'FontSize', 8, 'HorizontalAlignment', 'right', ...
'Color', color{i,j}); % use braces instead of parentheses.
See the FAQ for a good explanation of when to use braces or parentheses: http://matlab.wikia.com/wiki/FAQ#What_is_a_cell_array.3F
  1 件のコメント
SG
SG 2015 年 5 月 15 日
That's even better, but I have already accepted an answer. I was convinced I had tried that, but looks like I hadn't. Thank you!

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