How to solve rachford - race function using newton method

1 回表示 (過去 30 日間)
Ruslan
Ruslan 2024 年 11 月 25 日
コメント済み: Ruslan 2024 年 11 月 26 日
I am beginner in MatLab. I don't understand how to define this function. I need to find value of fRg. I have massives with values of ci and Ki.

採用された回答

Torsten
Torsten 2024 年 11 月 25 日
編集済み: Torsten 2024 年 11 月 25 日
Multiply the equation by product_{i=1}^{n_c} (1+f_Rg*(K_i-1)). This gives you a polynomial of degree n_c-1 in f_Rg which can be solved using the "roots" function.
Or if you are lazy, just use:
K = [3 5 -7 9 -10 2];
c = [0.4 0.6 1.2 -0.7 1.1 0.8];
syms f_Rg
fun = sum(c.*(K-1)./(1+f_Rg*(K-1)));
f_Rg_num = double(solve(fun==0,f_Rg))
f_Rg_num =
0.1072 + 0.0000i -0.1606 - 0.0949i -0.1606 + 0.0949i -0.4091 + 0.0000i -0.7971 + 0.0000i
But don't use Newton's method in this case because the equation has nc-1 solutions, and it were pure luck if Newton's method converged to the "correct" one.
  3 件のコメント
Torsten
Torsten 2024 年 11 月 26 日
編集済み: Torsten 2024 年 11 月 26 日
Your equation rewritten is a polynomial of degree n_c-1 in the variable f_Rg. A polynomial can have real and complex roots. A value for the "i" component in the solution for f_Rg_num that is different from 0 indicates complex roots. You will have to sort out the "correct" solution for your case from the n_c-1 solutions returned.
Ruslan
Ruslan 2024 年 11 月 26 日
Oh. Now I understand. Thank you. Actual answer is in range from 0 to 1, so it will be easy to sort. Thank you for your help!

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeSymbolic Math Toolbox についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by