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if the cell duplicated put last column in the previous row

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Amr Hashem
Amr Hashem 2015 年 5 月 12 日
コメント済み: Walter Roberson 2015 年 5 月 14 日
i run this code but it gives an error:
j=1;
rowsize=length(defs);
data1=cell([rowsize,C2]); % create array with size [R,C]
for j=1:length(defs) % loop over Mdr of defib
querymdr=data2{j,1}; % save MDR numbers
y=alldata{:,1};
idx= find(y==querymdr); % find in alldata MDR equals def
record=[alldata{idx(1),:}]; % copy the 1st search result
for k=2:length(idx)% over all MDR number of text
record = [record,(alldata(idx(k),6))];
end
data1(j,:)=record; % put combined record into result table
end
what is the wrong thing ?
  5 件のコメント
Walter Roberson
Walter Roberson 2015 年 5 月 14 日
What is class(y) and size(y) when the problem occurs?
Also your code does not account for the possibility of there being no match.
Amr Hashem
Amr Hashem 2015 年 5 月 14 日
i adjust the code to be :
for j=1:length(defs)
querymdr=data2(:,1);
y=alldata(:,1);
idx= find(y==querymdr); % find matched cells
record= alldata(idx,:);
it gives me an error in idx= find(y==querymdr); % y has 37*1 cell and querymdr has 5*1 cell
they are matched columns, but y has 37 cell and querymdr has 5 only. i want to find the matched cells.
what is wrong?

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採用された回答

James Tursa
James Tursa 2015 年 5 月 14 日
Maybe idx is empty (i.e., the find didn't result in a match). Do this to verify:
dbstop if error
Then run your code. When the error occurs, the execution will pause and you can examine variable sizes to confirm the problem and why it occurred.
  2 件のコメント
Amr Hashem
Amr Hashem 2015 年 5 月 14 日
i adjust the code to be :
for j=1:length(defs)
querymdr=data2(:,1);
y=alldata(:,1);
idx= find(y==querymdr); % find matched cells
record= alldata(idx,:);
it gives me an error in idx= find(y==querymdr); % y has 37*1 cell and querymdr has 5*1 cell
what is wrong?
Walter Roberson
Walter Roberson 2015 年 5 月 14 日
You created a new Question for this, so no point answering here.

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