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N/A
N/A 2024 年 10 月 30 日
Locked: John D'Errico 2024 年 10 月 30 日
Use the eye command to create the array E shown on the left below. Then use the colon to address elements in the arrays and the eye command to change E to match the array shown on the right.
1 0 0 0 0 0
0 1 0 0 0 0
E = 0 0 1 0 0 0
0 0 0 1 0 0
0 0 0 0 1 0
0 0 0 0 0 1
1 0 0 1 0 0
0 1 0 0 1 0
E = 0 0 1 0 0 1
1 0 0 1 0 0
0 1 0 0 1 0
0 0 1 0 0 1

回答 (1 件)

Yash
Yash 2024 年 10 月 30 日
編集済み: Yash 2024 年 10 月 30 日
This seems to be an assignment question. Therefore, I won't be providing the exact solution, I will provide you a few resources which will help you in solving it.
The "eye" command is used to get an identity matrix in MATLAB. To see its details, please refer to the following documentation: https://www.mathworks.com/help/matlab/ref/eye.html.
For example, the following command can generate an 5*5 identity matrix:
E = eye(5)
E = 5×5
1 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 1
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Now you can use colon for indexing/slicing the matrix and assigning a value to it.
For example, the follwing code assigns four 2's in the array E:
E(2:3,1:2) = [2 2;2 2]
E = 5×5
1 0 0 0 0 2 2 0 0 0 2 2 1 0 0 0 0 0 1 0 0 0 0 0 1
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You can refer to the following documentation for more details on indexing: https://www.mathworks.com/help/matlab/learn_matlab/array-indexing.html.
Please try to use the eye function and the colon operator to get the desired results.
Hope this helps!

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