How to create a symmetric 2D distribution from a novel distribution

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Sebastian Daneli
Sebastian Daneli 2024 年 10 月 9 日
コメント済み: Torsten 2024 年 10 月 10 日
この 質問 は Sebastian Daneli さんによってフラグが設定されました
Hi
I have a distribution, lets call it f, represented as a vector. Essentially I would like to turn this into a point spread function to deconvolute some images. For this i need a symmetric 2D distribution of this distribution from above. How do I effectively accomplish this? I share my function bellow, it that is of any help.
Thanks in advance
load('f.mat');
figure()
plot(f)
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John D'Errico
John D'Errico 2024 年 10 月 9 日
編集済み: John D'Errico 2024 年 10 月 9 日
What does it mean (in terms of mathematics) to get a uniform 2-d distribution, from something that is distinctly not uniform? I'm sorry, but you are asking to do something that makes no mathematical sense. It might be a question of knowing the right language, whatever. But it means you need to explain far more clearly what you want to do.

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回答 (1 件)

the cyclist
the cyclist 2024 年 10 月 9 日
編集済み: the cyclist 2024 年 10 月 9 日
I agree with @John D'Errico that we need more description. Do you just mean that you want to replicate f across another dimension? Like this?
load('f.mat','f')
f2 = repmat(f,1,10);
surf(f2)
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Sebastian Daneli
Sebastian Daneli 2024 年 10 月 10 日
編集済み: Sebastian Daneli 2024 年 10 月 10 日
@John D'Errico, yes, that's what I meant. Symmetry is what I was thinking about, not uniformity.
Torsten
Torsten 2024 年 10 月 10 日
Should your data be the y-values of a probability density function ? If yes: what are the corresponding x-values ?

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