Hi, can anyone help me with this problem? We need the smallest positive real root of this equation
a*x^4+b*x^3+c*x^2+d*x+e=0,
where a>0, b<0, c>0, d<0 and e>0. As Descartes said, in that case this equation has at least 2 positive real roots.
Thank you for your attention.

 採用された回答

Walter Roberson
Walter Roberson 2011 年 11 月 18 日

1 投票

r = roots([a,b,c,d,e]);
r(imag(r)~=0) = []; %remove complex
r(r <= 0) = []; %remove non-positive
min(r) %now it is the smallest positive real root

5 件のコメント

Asatur Khurshudyan
Asatur Khurshudyan 2011 年 11 月 18 日
Thank you very much Mr. Robertson.
Could you, please, find the root in the case of a>0, b<0, c>0, d<0 and e>0.
Walter Roberson
Walter Roberson 2011 年 11 月 18 日
Are the coefficients symbolic variables or actual values? The above code is for actual values. If you are asking for the general symbolic solution, then sorry, I do not know if it is possible; I can see from unconstrained solution to the roots that it would be quite quite messy if it can be done.
Asatur Khurshudyan
Asatur Khurshudyan 2011 年 11 月 19 日
Yes, unfortunately they are symbolic variables, otherwise, there is Ferrary`s method for its solving, but it`s very difficult. If you have a bit of free time, please try it for us for symbolic coefficients, we shall be very grateful.
Walter Roberson
Walter Roberson 2011 年 11 月 19 日
I think I do not know enough polynomial theory to come up with a useful answer on this, sorry.
Asatur Khurshudyan
Asatur Khurshudyan 2011 年 11 月 20 日
No, I mean with Matlab. If there exist exact method, than it must be done by mathlab, I suppose. All right, as you wish.

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

ヘルプ センター および File ExchangeSymbolic Math Toolbox についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by