Huffman coding and decoding for image(JPEG, BMP)

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Manisha Mehra
Manisha Mehra 2011 年 2 月 28 日
コメント済み: Harshil Patel 2020 年 4 月 28 日
I have to implement huffman encoding and decoding for a '.bmp' image without using the inbuilt matlab function like huffmandict, huffmanenco and huffmandeco.
Can anybody help me by sending me the source code?
Moreover, I have done the encoding part but I am not able to do the decoding. I have no idea as how to reconstruct the image through decoding.
  4 件のコメント
Jasmina Vanasiwala
Jasmina Vanasiwala 2016 年 12 月 12 日
I have to implement huffman encoding and decoding for a 'jpeg' image using C or C++. Please anyone help me by sending the source code?
Walter Roberson
Walter Roberson 2016 年 12 月 12 日
  1. this is a resource for MATLAB questions not C or C++
  2. there are already a lot of public sources for that task including libjpeg
  3. if we send you source then you would not have implemented it. Would we get the academic credit or would you?

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採用された回答

Paulo Silva
Paulo Silva 2011 年 2 月 28 日
  2 件のコメント
Manisha Mehra
Manisha Mehra 2011 年 3 月 1 日
Thanks..
It worked awesome.
fateh
fateh 2014 年 11 月 9 日
how could i run this example

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その他の回答 (2 件)

Falak
Falak 2012 年 5 月 4 日
Try this one... just change to your required image
%Author Name:Falak Shah
%Target: To huffman encode and decode user entered string
%--------------------------------------------------------------------------
string=input('enter the string in inverted commas'); %input string
symbol=[]; %initialise variables
count=[];
j=1;
%------------------------------------------loop to separate symbols and how many times they occur
for i=1:length(string)
flag=0;
flag=ismember(symbol,string(i)); %symbols
if sum(flag)==0
symbol(j) = string(i);
k=ismember(string,string(i));
c=sum(k); %no of times it occurs
count(j) = c;
j=j+1;
end
end
ent=0;
total=sum(count); %total no of symbols
prob=[];
%-----------------------------------------for loop to find probability and
%entropy
for i=1:1:size((count)');
prob(i)=count(i)/total;
ent=ent-prob(i)*log2(prob(i));
end
var=0;
%-----------------------------------------function to create dictionary
[dict avglen]=huffmandict(symbol,prob);
% print the dictionary.
temp = dict;
for i = 1:length(temp)
temp{i,2} = num2str(temp{i,2});
var=var+(length(dict{i,2})-avglen)^2; %variance calculation
end
temp
%-----------------------------------------encoder and decoder functions
sig_encoded=huffmanenco(string,dict)
deco=huffmandeco(sig_encoded,dict);
equal = isequal(string,deco)
%-----------------------------------------decoded string and output
%variables
str ='';
for i=1:length(deco)
str= strcat(str,deco(i));
end
str
ent
avglen
var
  8 件のコメント
Walter Roberson
Walter Roberson 2019 年 3 月 23 日
What leads you to say that it does not work?
Harshil Patel
Harshil Patel 2020 年 4 月 28 日
I ran the code in matlab 2020a, and it generated some otput with some values for str, ent, avglen and var for an image input. So, how do I know if it's correct?

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slama najla
slama najla 2012 年 5 月 19 日
Hello please is that you can help me? is that you can send me your registration code files before you get the picture compressed as I encounter the same problem as let go of compressed image is a very superior picture framer and my original remark that the fault is in the recording files. thank you in advance
  9 件のコメント
Walter Roberson
Walter Roberson 2019 年 11 月 26 日
SS
SS 2019 年 11 月 27 日
rng('default') % For reproducibility
X = rand(10,3);
In this code, what will be the value of X for my image..???

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