expressing the complex function

1 回表示 (過去 30 日間)
yogeshwari patel
yogeshwari patel 2024 年 10 月 5 日
コメント済み: yogeshwari patel 2024 年 10 月 5 日
clear i
syms x t
U=zeros(1,2,'sym');
A=zeros(1,2,'sym');
series(x,t)=sym(zeros(1,1));
U(1)=exp(i*x);
alpha=1;
for k=1:2
A(1)=0;
for r=1:k
for s=1:r
A=A+U(s)*U(r-s+1)*U(k-r+1);
end
end
U(k+1)=simplify(i*(gamma(alpha*(k-1)+1)/gamma((alpha*(k))+1))*(sym(1/2)*diff(U(k),x,2)))
end
for k=1:3
series(x,t)=simplify(series(x,t)+U(k)*power(t,k-1))
end
series i obatin is form of the complex function and want to separte the real and imigimary part of the complex number But the command Re(series) does work . I want to plot the graph of the real part and imaginary part separtely of the series . For that i use the command expand (series) but it is also not working

採用された回答

Torsten
Torsten 2024 年 10 月 5 日
移動済み: Torsten 2024 年 10 月 5 日
Use
syms x t real
instead of
syms x t
Then real(series) and imag(series) will work.

その他の回答 (1 件)

Walter Roberson
Walter Roberson 2024 年 10 月 5 日
You can use real() and imag(), but they will not help much.
A problem is that you do not constrain x or t to be real-valued, so real() and imag() are not able to simplify the expressions.
  5 件のコメント
Torsten
Torsten 2024 年 10 月 5 日
syms x t
U=zeros(1,2,'sym');
U(1)=cos(x)+1i*sin(x)
yogeshwari patel
yogeshwari patel 2024 年 10 月 5 日
Thanks

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeCalculus についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by