Newton Forward difference method

10 ビュー (過去 30 日間)
Sunday
Sunday 2024 年 9 月 15 日
編集済み: Torsten 2024 年 9 月 15 日
% Confirmed case Sample data points (x, y)
data = [ 1, 88; 2, 49; 3, 47; 4, 8; 5, 34; 6, 762; 7, 98; 8, 40];
% Extract x and y values
x = data(:, 1);
y = data(:, 2);
n = length(x);
% Calculate forward differences
forward_diff = zeros(n, n);
forward_diff(:, 1) = y;
for j = 2:n
for i = 1:n-j+1
forward_diff(i, j) = forward_diff(i+1, j-1) - forward_diff(i, j-1);
end
end
% Construct the Newton Forward Difference polynomial
syms X;
P = y(1);
for j = 1:n-1
term = forward_diff(1, j);
for i = 1:j
term = term * (X - x(i));
end
P = P + term / factorial(j);
end
disp('Newton Forward Difference Polynomial:');
Newton Forward Difference Polynomial:
disp(simplify(P));
Result Newton Forward Difference Polynomial: - (725*X^7)/1008 + (1651*X^6)/80 - (173233*X^5)/720 + (70651*X^4)/48 - (91321*X^3)/18 + (146407*X^2)/15 - (1996741*X)/210 + 3658
The problem now is that when I substitute each value of x, I don't get the corresponding value of y as stated in the table. I need help on how to get the correct polynomial equation.

採用された回答

Torsten
Torsten 2024 年 9 月 15 日
編集済み: Torsten 2024 年 9 月 15 日
Three coding errors:
% Confirmed case Sample data points (x, y)
data = [ 1, 88; 2, 49; 3, 47; 4, 8; 5, 34; 6, 762; 7, 98; 8, 40];
% Extract x and y values
x = data(:, 1);
y = data(:, 2);
n = length(x);
% Calculate forward differences
forward_diff = zeros(n, n);
forward_diff(:, 1) = y;
for j = 2:n
for i = 1:n-j+1
%forward_diff(i, j) = (forward_diff(i+1, j-1) - forward_diff(i, j-1))
forward_diff(i, j) = (forward_diff(i+1, j-1) - forward_diff(i, j-1)) / (x(i+j-1) - x(i));
end
end
% Construct the Newton Forward Difference polynomial
syms X;
P = y(1);
for j = 1:n-1
%term = forward_diff(1, j);
term = forward_diff(1, j+1);
for i = 1:j
term = term * (X - x(i));
end
%P = P + term / factorial(j);
P = P + term;
end
disp('Newton Forward Difference Polynomial:');
Newton Forward Difference Polynomial:
disp(simplify(P));
double(subs(P,X,x))
ans = 8×1
88 49 47 8 34 762 98 40
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
For all data series with deltax = 1 (as the one above), there is one error in your code. But note that this is a special case and the above code holds for arbitrary deltax.
% Confirmed case Sample data points (x, y)
data = [ 1, 88; 2, 49; 3, 47; 4, 8; 5, 34; 6, 762; 7, 98; 8, 40];
% Extract x and y values
x = data(:, 1);
y = data(:, 2);
n = length(x);
% Calculate forward differences
forward_diff = zeros(n, n);
forward_diff(:, 1) = y;
for j = 2:n
for i = 1:n-j+1
forward_diff(i, j) = forward_diff(i+1, j-1) - forward_diff(i, j-1);
end
end
% Construct the Newton Forward Difference polynomial
syms X;
P = y(1);
for j = 1:n-1
%term = forward_diff(1, j);
term = forward_diff(1, j+1);
for i = 1:j
term = term * (X - x(i));
end
P = P + term / factorial(j);
end
disp('Newton Forward Difference Polynomial:');
Newton Forward Difference Polynomial:
disp(simplify(P));
double(subs(P,X,x))
ans = 8×1
88 49 47 8 34 762 98 40
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeNumber Theory についてさらに検索

製品


リリース

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by