I shouldn't convert the cell array to array. Is there any function to sort the array based on last column directly? or at least sort the first column (string column) based on last column.
How can I sort this cell Array?
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Hello
I have a cell arraye like this:
ca{1,1}={'x' ;'y'; 'z'};
ca{1,2}=[1 1 9 3;...
5 1 1 1;...
5 7 5 9];
ca{1,3}={13; 14 ; 10};
How can I sort this cell Array based on last column ( ca{1,3})?
採用された回答
Andrei Bobrov
2015 年 5 月 4 日
[~,ii] = sort(cat(1,ca{3}{:}));
out = cellfun(@(x)x(ii,:),ca,'un',0);
3 件のコメント
Michael Haderlein
2015 年 5 月 5 日
It applies a function on each element of a cell. The cell is ca and the function is @(x)x(ii,:). x is the cell element here. So in the end, it just applies the sorting array ii on each element of the cell. The 'un',0 is an additional parameter which is required whenever the output is a cell and not a numerical array. Just play with cellfun, you'll understand it easily.
その他の回答 (2 件)
dpb
2015 年 5 月 4 日
>> [~,ix]=sort(cell2mat(ca{1,3}));
>> ca{1,2}=ca{1,2}(ix,:);
>> ca{1,2}
ans =
5 1 1 1
5 7 5 9
1 1 9 3
>>
Having the last cell as an array of three elements instead of a 3-vector makes it tougher--otherwise could do away w/ the cell2mat and just use the curlies to address the cell for sorting.
0 件のコメント
Afsane Afsane
2015 年 5 月 4 日
編集済み: Afsane Afsane
2015 年 5 月 4 日
8 件のコメント
Mohammad Abouali
2015 年 5 月 5 日
編集済み: Mohammad Abouali
2015 年 5 月 5 日
cat(1,ca{3}{:}) in Andrei Bobrov's answer is still converting a cell array to regular array then sorts it. That's not any different than dpb's first answer using cell2mat.
The problem is that she wants to do it without any conversion to other data format.
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