Problem in numerical integration

1 回表示 (過去 30 日間)
Habib
Habib 2015 年 5 月 1 日
Hi every one.
I want to by means of "Trapz" do numerical integration but when I plot the result data, its shape is not what I want. in my code, u1 is my function that I wanted to do integration of it. I do double integration, first is based on y1 and second is base on x1. If u1 is plotted, it is not same of u2 shape. I couldn't detect codes defect. so, who can help me?
close all
clear all
clc
N=100;
x1=linspace(-1,1,N);
y1=x1;
z=0.42;
lambda=1030e-9;
k=2*pi/lambda;
w0=0.1;
zr=pi*w0.^2/lambda;
R=z*(1+(zr/z).^2);
w=w0*sqrt(1+(z/zr)^2);
[x,y]=meshgrid(linspace(-1,1,N));
[x2,y2]=meshgrid(linspace(-1,1,N));
r=sqrt(x.^2+y.^2);
teta=atan(y./x);
r1=sqrt(x2.^2+y2.^2);
teta1=atan(y2./x2);
u1=ones(N,N);
u=u1;
u_2=u;
u2=u;
B=u;
for i=1:N
for j=1:N
u(i,j)=(r(i,j)/w).*exp(-(r(i,j)/w).^2);
B(i,j)=besselj(1,-k.*r(i,j).*r1(i,j)./z);
u1(i,j)=r(i,j).*u(i,j).*exp(-1i*k*(r(i,j)./w).^2./(2*z)).*B(i,j);
end
end
for i=1:N
for j=1:N
u_2(:,j)=trapz(y1,u1(:,j));
end
u2(i,:)=cos(teta1(i,j)).*(-k/z).*exp(-1i*k.*(r1(i,:)./w).^2./(2*z)).*trapz(x1,u_2(i,:));%
end

回答 (0 件)

カテゴリ

Help Center および File ExchangeNumerical Integration and Differentiation についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by