How to count the number of non-nan values for combination of multiple variables
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Hello, I would like to count the number of non-nan values in the d column for unique combinations of a, b and c (i.e I want to generate the e column in tt). If any a,b or c are NaN then the count should be nan as well
% Initial table
a = [1,1,1,2,2,2,2]';
b = [660, 661, 661, 663, 663, NaN, 663]';
c = [1,2,2,5,5,NaN,6]';
d = [11,12,NaN, 13, 14, NaN,5]';
t = table(a,b,c,d)
% Desired output
a = [1,1,1,2,2,2,2]';
b = [660, 661, 661, 663, 663, NaN, 663]';
c = [1,2,2,5,5,NaN,6]';
d = [11,12,NaN, 13, 14, NaN,5]';
e = [1, 1, 1, 2, 2, NaN, 1]';
tt = table(a,b,c,d,e)
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Voss
2024 年 7 月 17 日
編集済み: Voss
2024 年 7 月 17 日
% Initial table
a = [1;1;1;2;2;2;2];
b = [660; 661; 661; 663; 663; NaN; 663];
c = [1;2;2;5;5;NaN;6];
d = [11;12;NaN; 13; 14; NaN;5];
t = table(a,b,c,d)
G = {'a','b','c'};
F = @(x)nnz(~isnan(x));
T = groupsummary(t,G,F,'d');
[~,~,idx] = unique(t(:,G),'rows');
e = T.fun1_d(idx);
e(any(isnan(t{:,G}),2)) = NaN;
tt = addvars(t,e)
その他の回答 (1 件)
J. Alex Lee
2024 年 7 月 17 日
編集済み: J. Alex Lee
2024 年 7 月 17 日
Not sure what d and e need to be, but i think this should at least partially help
a = [1,1,1,2,2,2,2]';
b = [660, 661, 661, 663, 663, NaN, 663]';
c = [1,2,2,5,5,NaN,6]';
x = [a,b,c]
% any(_,2) goes row-wise ORs.
any(isnan(x),2)
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