splitting large cell array into smaller cell arrays

4 ビュー (過去 30 日間)
Aditya
Aditya 2015 年 4 月 27 日
コメント済み: Aditya 2015 年 4 月 27 日
hi
I have a large cell array "a" (5290*1) such that each element of the array is of size e.g. size(a{1,1}) = 21*204
i want to split these further such that each element of a{1,1} contains another cell array such that size of a{1,1}.b1 = 3*204 and i have a{1,1}.b1, a{1,1}.b2.... a{1,1}.b7 so a{1,1} contains 7 cells of size 3*204. how can i achieve this without for loop?
Many thanks for you help.

採用された回答

Michael Haderlein
Michael Haderlein 2015 年 4 月 27 日
If you really want to have the inside to be a struct, you can go with
c=cellfun(@(x) cell2struct(mat2cell(x,3*ones(7,1),204),{'b1','b2','b3','b4','b5','b6','b7'}),a,'uniform',false);
For sure, the {'b1'...'b7'} can be done nicer (ask if you need help with that).
Anyway, most likely it's better to keep the internal to be cells, then the upper code simplifies to
c=cellfun(@(x) mat2cell(x,3*ones(7,1),204),a,'uniform',false);

その他の回答 (1 件)

Guillaume
Guillaume 2015 年 4 月 27 日
Use mat2cell to split your matrices into cells. This assumes that all matrices are the same size:
newa = cellfun(@(m) mat2cell(m, 3*one(1, 7), 204), a, 'UniformOutput', false)

カテゴリ

Help Center および File ExchangeMatrices and Arrays についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by