How to use previous answer in new calculation n times
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Hi all
I am pretty new to Matlab and have been struggling with loops and arrays.
My issue is I am attempting to calculate yn where x in the original calculation becomes y1 in caclulation for y2 and so on.
ie:
x = [1;2] %orginal value
it then is multiplied by A= [0.3 -0.2; -0.6 -0.8]
and B=[-14;2] is added to it to become y1, then calculation is repeated and rather than using x, y1 used to calculate y2 and so on.
Any help would be greatly appreciated.
clear; clc; close all;
A=[0.3 -0.2; -0.6 0.8];
B=[-14;2];
x=[1;2];
y1=A*x+B
y2=A*y1+B
y3=A*y2+B
y4=A*y3+B
y5=A*y4+B
y6=A*y5+B
y7=A*y6+B
y8=A*y7+B
y9=A*y8+B
y10=A*y9+B
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採用された回答
Star Strider
2024 年 6 月 10 日
Perhaps something like this —
A=[0.3 -0.2; -0.6 0.8];
B=[-14;2];
x=[1;2];
y = x;
for k = 1:10
y = A*y+B;
ym(:,k) = y; % Y-Matrix: 'ym'
end
ym
figure
plot((1:10), ym)
grid
legend('y(1)','y(2)', 'Location','best')
.
4 件のコメント
David Goodmanson
2024 年 6 月 11 日
編集済み: David Goodmanson
2024 年 6 月 12 日
Hi Chris,
A key feature of the answer is that there are not nine different variables y1,y2, ... using all those variables is called dynamic variable naming and it is highly discouraged. Instead you have one matrix variable. Any of the previous variables, for example y4, can easily be accessed since it is ym(:,4). (The use of a colon here means every row in column 4).
その他の回答 (1 件)
Paul
2024 年 6 月 12 日
A=[0.3 -0.2; -0.6 0.8];
B=[-14;2];
x=[1;2];
sys = ss(A,B,eye(2),0,-1);
y = lsim(sys,ones(11,1),0:10,x); % y0 = x
%y = step(sys,10) + initial(sys,x,10); % y0 = x; alternative method
figure
plot(0:10,y)
0 件のコメント
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