problem in function inputs

2 ビュー (過去 30 日間)
naiva saeedia
naiva saeedia 2024 年 5 月 19 日
編集済み: naiva saeedia 2024 年 5 月 19 日
Hi guys. I have this function that gives me the equations for my DAE system.
function S = Sec_model_fun(t,x,Q0,T1)
%%Dynamic state inputs
n_C2_gas=x(1); %Ethylene mols in gas phase[mol]
n_C4_gas=x(2); %Butene mols in gas phase[mol]
n_C6_gas=x(3); %Hexene mols in gas phase[mol]
n_C8_gas=x(4); %Octene mols in gas phase[mol]
n_C10_gas=x(5); %Decene mols in gas phase[mol]
n_C12_gas=x(6); %Dodecene mols in gas phase[mol]
n_C11_gas=x(7); %Undecene mols in gas phase[mol]
n_C2_liquid=x(8); %Ethylene mols in liquid phase[mol]
n_C4_liquid=x(9); %Butene mols in liquid phase[mol]
n_C6_liquid=x(10); %Hexene mols in liquid phase[mol]
n_C8_liquid=x(11); %Octene mols in liquid phase[mol]
n_C10_liquid=x(12); %Decene mols in liquid phase[mol]
n_C12_liquid=x(13); %Dodecene mols in liquid phase[mol]
n_C11_liquid=x(14); %Undecene mols in liquid phase[mol]
e_integral = x(15); %Error[mol/s]
%FGout = x(16); %Gas outlet[mol/s]
%% Constants
Kc_Total_gases = 1;
tauI_Total_gases =1;
%Q0=350; % Q_G etylene inflow (ml/min)
Q1=Q0*1e-6/60; % Q_G ethylene inflow (m3/s)
Q2=0; % Q_G butene inflow
Q3=0; % Q_G hexene inflow
Q4=0; % Q_G octene inflow
Q5=0; % Q_G decene inflow
Q6=0; % Q_G dodecene inflow
Q7=0; % Q_G undecane inflow
P1=36e5; % ethylene inflow pressure [Pa]
%T1=230+273.15; % T_Ethylene [K]
T2=230+273.15; % T_ref [K]
R=8.314; % gas constant [J/(mol.K)]
C1=P1/(R*T1); % ethylene inlet gas concentration [mol/m^3]
F0=0.0179; % gas outflow rate [mmol/s]
F1=F0.*1e-3; % gas outflow rate [mol/s]
VR=300e-6; % reactor volume [m^3]
VG=250e-6; % gas volume [m^3]
VL=50e-6; % liquid volume [m^3]
K=[3.24;2.23;1.72;0.2;0.1;0.08;0.09]; % solubility [nondim]
moleWt=[28;56;84;112;140;168;156]; % mole weight C2,C4,...,C12,C11 [g/mol]
wc=(0.3+0.25)*1e-3; % catalyst weight [kg]
kref=[2.224e-4;1.533e-4;3.988e-5;1.914e-7;4.328e-5;...
2.506e-7;4.036e-5;1.062e-6;6.055e-7;]; % rate at Tref=230C [mol/(s.g_cat)]
Eact=[109.5; 15.23; 7.88; 44.45; 9.438; 8.426; 10.91; 12.54; 7.127]; % activation energy [J/mol];
k=kref.*exp(-Eact*(1/T1-1/T2)/R); % rate at T=T2 [mol/(s.g)]
kL=1; kH=1;
% Specify initial conditions
xinit=zeros(15,1); % initial state vector
xinit(1)=C1*VR; % initial ethylene in gas (mol)
xinit(14)=36.63/156; % initial undecane in liquid (mol)
xinit(7) = xinit(14)*VG*K(7)/VL; % initial undecane in gas (mol)
xinit(8) = xinit(1)*VL/(K(1)*VG); % initial ethylene in liquid (mol)
xinit(15)=Q1*C1; % initial outflow rate (mol/s)
nToti=sum(xinit(1:7)); % initial moles in gas (mol)
%%Setpoint
nGin_setpoint=0.363839693638512;
%Set Point Tracking & Load Rejection
%t1 = 1800; t2 = 3600; t3 = 5400; t4 = 7200; t5 = 9000; t6 = 10800; t7 = 12600; t8 = 14400; t9 = 16200; t10 = 18000;
% Step 1
% +5% change in set point
%if t >= t1 && t <= t2
% nGin_setpoint = 0.616018502797380*1.05;
% Step 2
% -5% change in set point and disturbance
%elseif t >= t3 && t <= t4
% nGin_setpoint = 0.616018502797380*0.95;
% Step 3
% +10% change in setpoint
%elseif t >=t5 && t<= t6
% nGin_setpoint = 0.616018502797380*1.1;
% Step 4
% -10% change in set point
%elseif t >=t7 && t <= t8
% nGin_setpoint = 0.616018502797380*0.9;
% Step 5
% +20% change in set point
%elseif t >= t9 && t <= t10
% nGin_setpoint = 0.616018502797380*1.2;
%end
e_mol_gases = sum(x(1:7)) - nGin_setpoint;
F_G_R = Kc_Total_gases*(e_mol_gases+tauI_Total_gases*e_integral);
%Right-hand side evaluation of the dynamic model (DAE set)
S1 = Q1*C1-F_G_R*x(1)/sum(x(1:7))-VR*kL*(x(1)/VG-K(1)*x(8)/VL); % gas phase ethylene (mol/s)
S2 = Q2-F_G_R*x(2)/sum(x(1:7))-VR*kL*(x(2)/VG-K(2)*x(9)/VL); % gas phase butene (mol/s);
S3 = Q3-F_G_R*x(3)/sum(x(1:7))-VR*kL*(x(3)/VG-K(3)*x(10)/VL); % gas phase hexene (mol/s);
S4= Q4-F_G_R*x(4)/sum(x(1:7))-VR*kH*(x(4)/VG-K(4)*x(11)/VL); % gas phase octene (mol/s);
S5= Q5-F_G_R*x(5)/sum(x(1:7))-VR*kH*(x(5)/VG-K(5)*x(12)/VL); % gas phase decene (mol/s);
S6= Q6-F_G_R*x(6)/sum(x(1:7))-VR*kH*(x(6)/VG-K(6)*x(13)/VL); % gas phase dodecene (mol/s);
S7= Q7-F_G_R*x(7)/sum(x(1:7))-VR*kH*(x(7)/VG-K(7)*x(14)/VL); % gas phase undecane (mol/s) ;
S8= VR*kL*(x(1)/VG-K(1)*x(8)/VL)+wc*(-2*k(1)*x(8)^2/VL^2-k(2)*x(8)*x(9)/VL^2-k(3)*x(8)*x(10)/VL^2-k(5)*x(8)*x(11)/VL^2-k(7)*x(8)*x(12)/VL^2);
S9= VR*kL*(x(2)/VG-K(2)*x(9)/VL)+wc*(k(1)*x(8)^2/VL^2-k(2)*x(8)*x(9)/VL^2-2*k(4)*x(9)^2/VL.^2-k(6)*x(9)*x(10)/VL^2-k(8)*x(9)*x(11)/VL^2);
S10= VR*kL*(x(3)/VG-K(3)*x(10)/VL)+wc*(k(2)*x(8)*x(9)/VL^2-k(3)*x(8)*x(10)/VL^2-k(6)*x(9)*x(10)/VL.^2-2*k(9)*x(10)^2/VL^2);
S11= VR*kH*(x(4)/VG-K(4)*x(11)/VL)+wc*(k(3)*x(8)*x(10)/VL^2+k(4)*x(9)^2/VL^2-k(5)*x(8)*x(11)/VL^2-k(8)*x(9)*x(11)/VL^2);
S12= VR*kH*(x(5)/VG-K(5)*x(12)/VL)+wc*(k(5)*x(8)*x(11)/VL^2+k(6)*x(9)*x(10)/VL^2-k(7)*x(8)*x(12)/VL^2);
S13= VR*kH*(x(6)/VG-K(6)*x(13)/VL)+wc*(k(7)*x(8)*x(12)/VL^2+k(8)*x(9)*x(11)/VL^2+k(9)*x(10)^2/VL^2);
S14= VR*kH*(x(7)/VG-K(7)*x(14)/VL);
S15= sum(x(1:7))-(nGin_setpoint); %Error
S = ([S1; S2; S3; S4; S5; S6; S7; S8; S9; S10; S11; S12; S13; S14; S15]);
end
I want to solve the S1,S2,..,S15 equations for different Q0 and T1. I have tried this code:
clear variables
clc
%Initial Condition
Q0=350; T1=230;
%S = @Sec_model_fun_for_optimization;
%S1 = S(Q0,T1);
y0 = [0.258176232100050 0 0 0 0 0 0.105663461538462 0.0159368044506204 0 0 0 0 0 0.234807692307692 0 Q0 T1];
%options = odeset('RelTol',1e-5,'AbsTol',1e-7);
[t,y]= ode23s(@Sec_model_fun_for_optimization,[0 18000],y0);
but I have got this error:
Not enough input arguments.
Error in Sec_model_fun_for_optimization (line 27)
Q1=Q0*1e-6/60; % Q_G ethylene inflow (m3/s)
As you can see I have done it in a wrong way and MATLAB can't recognize Q0 and T1 as my function inputs. What should I do to solve this problem??
  3 件のコメント
Torsten
Torsten 2024 年 5 月 19 日
編集済み: Torsten 2024 年 5 月 19 日
I guess It's correct answer??
Yes, that's the way extra parameters can be passed to your function.
naiva saeedia
naiva saeedia 2024 年 5 月 19 日
Thanks a lot for your answer🙏🏻

サインインしてコメントする。

採用された回答

naiva saeedia
naiva saeedia 2024 年 5 月 19 日
編集済み: naiva saeedia 2024 年 5 月 19 日
I have solved the problem. Here is the code:
clear variables
clc
%Initial Condition
Q0=100; T1=230;
%S = @Sec_model_fun_for_optimization;
%S1 = S(Q0,T1);
y0 = [0.258176232100050 0 0 0 0 0 0.105663461538462 0.0159368044506204 0 0 0 0 0 0.234807692307692 0];
%options = odeset('RelTol',1e-5,'AbsTol',1e-7);
[t,y]= ode23s(@(t,y) Sec_model_fun_for_optimization(t,y,Q0,T1),[0 18000],y0);%Initial ConditionQ0=100; T1=230;%S = @Sec_model_fun_for_optimization;%S1 = S(Q0,T1);y0 = [0.258176232100050 0 0 0 0 0 0.105663461538462 0.0159368044506204 0 0 0 0 0 0.234807692307692 0];%options = odeset('RelTol',1e-5,'AbsTol',1e-7);[t,y]= ode23s(@(t,y) Sec_model_fun_for_optimization(t,y,Q0,T1),[0 18000],y0);
  2 件のコメント
Torsten
Torsten 2024 年 5 月 19 日
This is the wrong one ...
naiva saeedia
naiva saeedia 2024 年 5 月 19 日
Sorry for that..I fixed it. Thanks for pointing it out🙏🏻

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeProgramming についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by