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how can i solve eps y''+ mu a(x) y'-b(x)y=f(x) with boundary condition y(0)=y(1)=0

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Dhayalan G
Dhayalan G 2024 年 5 月 9 日
コメント済み: Torsten 2024 年 5 月 14 日
i want to know the function code for reaction convection diffusion equation in ode with two paremeter epsilon and mu
  1 件のコメント
Sam Chak
Sam Chak 2024 年 5 月 9 日
Are you interested in learning how to code and then writing the function code yourself?
Or, would you prefer BVP experts in this forum to provide the full code with arbitrarily assigned values for the parameters eps, mu, a(x), b(x), and f(x)?
Clarifying this will help us determine the appropriate level of guidance to match your skill level.

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回答 (2 件)

sai charan sampara
sai charan sampara 2024 年 5 月 9 日
Hello Dhayalan,
The equations of the above form can be solved by using "diff" and "dsolve" functions in MATLAB. The "diff" function is used to define the first and seconder order derivatives of "y". Then the equation and the initial conditions are defined and solved using "dsolve". Here is an example:
syms y(x)
ode = 2*x^2*diff(y,x,2)+3*x*diff(y,x)-y-x== 0;
cond1 = y(0) == 0;
cond2 = y(1) == 0;
conds = [cond1 cond2];
ySol(x) = dsolve(ode,conds)
ySol(x) = 
  1 件のコメント
Torsten
Torsten 2024 年 5 月 9 日
And if a(x), b(x) and c(x) get too complicated, use "bvp4c".

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Areeba
Areeba 2024 年 5 月 14 日
import numpy as np
from scipy.sparse import diags
from scipy.sparse.linalg import spsolve
def solve_rcd_equation(epsilon, mu, a, b, f, x_min, x_max, N):
# Discretization
dx = (x_max - x_min) / (N - 1)
x = np.linspace(x_min, x_max, N)
# Constructing the differentiation matrix
diagonals = [[epsilon/dx**2], [-(epsilon/dx**2 + mu*a(x)/2*dx)], [epsilon/dx**2 + mu*a(x)/2*dx - b(x)]]
D = diags(diagonals, [-1, 0, 1], shape=(N, N)).toarray()
# Boundary conditions
D[0, 0] = 1
D[0, 1] = 0
D[-1, -1] = 1
D[-1, -2] = 0
# Right-hand side
rhs = f(x)
rhs[0] = 0
rhs[-1] = 0
# Solve the system
y = spsolve(D, rhs)
return x, y
# Example functions for a, b, and f
def a(x):
return 1
def b(x):
return 1
def f(x):
return np.sin(np.pi * x)
# Parameters
epsilon = 0.1
mu = 0.5
x_min = 0
x_max = 1
N = 100
# Solve the equation
x, y = solve_rcd_equation(epsilon, mu, a, b, f, x_min, x_max, N)
# Plot the solution
import matplotlib.pyplot as plt
plt.plot(x, y)
plt.xlabel('x')
plt.ylabel('y')
plt.title('Solution of Reaction-Convection-Diffusion Equation')
plt.grid(True)
plt.show()

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