How to match matrix elements for a condition?
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I am working on App Designer. I have a matrix and want to match the elements 3 by 3 with a condition. The condition is that addition of 3 elements must be near at a value.
I already can match them by making the addition from minimum to maximum, but it does not seem to be optimal. So, I want them to be around a value.
2 件のコメント
Dyuman Joshi
2024 年 4 月 22 日
Use tolerance to compare -
in = [3 3.3 3.6 3.9];
check = 3.5;
tol = 0.3;
out = abs(in-check)<tol
採用された回答
Torsten
2024 年 4 月 23 日
編集済み: Torsten
2024 年 4 月 23 日
If A becomes larger, this brute-force way of solving will become intractable.
A = [15 25 36 17 48 59 31 64 18 21 97 84 31 64 15];
target = 100;
C = nchoosek(1:numel(A),3);
P = arrayfun(@(i)sum(A(C(i,1:3))),1:size(C,1));
[~,I] = sort(abs(P-target));
sums = arrayfun(@(i)sum(A(C(I(i),:))),1:numel(I));
sums = sums(sums==sums(1));
n = numel(sums);
result = unique(sort(A(C(I(1:n),:)),2),'rows')
その他の回答 (1 件)
Hassaan
2024 年 4 月 22 日
Assuming a 1-dimensional array. Will check for sums of three consecutive elements that are close to a given value (target_sum) within a tolerance (tol).
% Example matrix (1D array)
A = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
% Target sum to match
target_sum = 15;
% Tolerance for matching sum
tol = 0.5;
% Length of the array
n = length(A);
% Pre-allocate the logical output array for matched cases
matches = false(1, n-2); % (n-2) because the last two elements can't start a triplet
% Iterate over the array to find matching triplets
for i = 1:n-2
% Calculate the sum of the current and next two elements
current_sum = sum(A(i:i+2));
% Check if the current sum is within the tolerance of the target sum
if abs(current_sum - target_sum) <= tol
matches(i) = true;
end
end
% Print matched triplets and their indices
matched_indices = find(matches);
for idx = matched_indices
fprintf('Match found at indices [%d, %d, %d]: [%d, %d, %d]\n', idx, idx+1, idx+2, A(idx), A(idx+1), A(idx+2));
end
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