Question on creating dynamic matrix variables
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Hi all, I would like to know how to write dynamic matrix variables. For example, I have the following:
clear all;
n=11
for i=1:n-1
A1(i,i+1) = 1;
A1(i+1,i) = 1;
end
A1
for i=1:n-2
A2(i,i+2) = 1;
A2(i+2,i) = 1;
end
A2
for i=1:n-3
A3(i,i+3) = 1;
A3(i+3,i) = 1;
end
A3
And I would like to make something like this:
for k=1:1:3
for i=1:n-1
A[k](i,i+1) = 1;
A[k](i+1,i) = 1;
end
end
Or alternatively, is there a neat way to do so?
採用された回答
Stephen23
2024 年 4 月 12 日
編集済み: Stephen23
2024 年 4 月 12 日
"Or alternatively, is there a neat way to do so?"
Of course there is: indexing. Either into a numeric array or into a container array (e.g. a cell array).
Indexing is neat, simple, and efficient. Unlike what you are trying to do.
n = 11; % size of each matrix
D = 2:4; % vector of indices of the 1's
C = cell(size(D));
for k = 1:numel(D)
V = zeros(1,n);
V(D(k)) = 1;
C{k} = toeplitz(V);
end
Checking:
C{1}
C{2}
C{3}
5 件のコメント
Stephen23
2024 年 4 月 12 日
Either modify the TOEPLITZ call with two vector inputs, or call DIAG:
n = 11; % size of each matrix
D = 1:3; % offset of the diagonal
C = cell(size(D));
for k = 1:numel(D)
C{k} = diag(ones(1,n-D(k)),D(k));
end
C{1}
C{2}
C{3}
その他の回答 (1 件)
Taylor
2024 年 4 月 12 日
May be worth looking into structures instead of matrices. https://www.mathworks.com/help/matlab/matlab_prog/generate-field-names-from-variables.html
0 件のコメント
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