How i can the value for x y z by using a matrix

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ABDUL
ABDUL 2024 ๅนด 3 ๆœˆ 29 ๆ—ฅ
ๅ›ž็ญ”ๆธˆใฟ: Gayatri 2024 ๅนด 4 ๆœˆ 2 ๆ—ฅ
calculate the values of the (x,y, and z) for the following 3*3 linear algebraic equation . Where the inputs are ๐‘Ž1โˆ’3, ๐‘1โˆ’3, ๐‘1โˆ’3, ๐‘Ž๐‘›๐‘‘ ๐‘ž1โˆ’3 ๐‘Ž๐‘  ๐‘ฃ๐‘’๐‘๐‘ก๐‘œ๐‘Ÿ๐‘ . ๐‘‚๐‘Ÿ๐‘”๐‘–๐‘›๐‘Ž๐‘™ ๐‘“๐‘œ๐‘Ÿ๐‘š ๐‘œ๐‘“ ๐‘’๐‘ž๐‘Ž๐‘ก๐‘–๐‘œ๐‘›๐‘  โˆถ ๐‘Ž1๐‘ฅ + ๐‘1๐‘ฆ + ๐‘1๐‘ง = ๐‘ž1 ๐‘Ž2๐‘ฅ + ๐‘2๐‘ฆ + ๐‘2๐‘ง = ๐‘ž2 ๐‘Ž3๐‘ฅ + ๐‘3๐‘ฆ + ๐‘3๐‘ง = ๐‘ž3 Try the code by entering different values of vectors.
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Dyuman Joshi
Dyuman Joshi 2024 ๅนด 3 ๆœˆ 29 ๆ—ฅ
How would you solve this on pen and paper utilizing concepts of Linear Algebra?

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Gayatri
Gayatri 2024 ๅนด 4 ๆœˆ 2 ๆ—ฅ
Hi Abdul,
To solve the given system of linear equations โˆถ ๐‘Ž1๐‘ฅ + ๐‘1๐‘ฆ + ๐‘1๐‘ง = ๐‘ž1, ๐‘Ž2๐‘ฅ + ๐‘2๐‘ฆ + ๐‘2๐‘ง = ๐‘ž2 and ๐‘Ž3๐‘ฅ + ๐‘3๐‘ฆ + ๐‘3๐‘ง = ๐‘ž3โ€‹, use the โ€˜linsolveโ€™ function.
function [x, y, z] = solveLinearEquations(a, b, c, q)
A = [a(1), b(1), c(1); a(2), b(2), c(2); a(3), b(3), c(3)];
Q = [q(1); q(2); q(3)];
solution = linsolve(A, Q);
x = solution(1);
y = solution(2);
z = solution(3);
end
Enter the different values for the coefficient vectors a, b, c and the constant vector q, then call the โ€˜solveLinearEquationsโ€™ function.
Please refer the below documentation for โ€˜linsolveโ€™ function:
I hope it helps!

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