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warning all the time, don't know what is wrong

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Xiao yang
Xiao yang 2024 年 3 月 22 日
コメント済み: Dyuman Joshi 2024 年 3 月 29 日
syms m n p a x y z lambda real
g = x + y + z -a;
L = (x).^m.*(y).^n.*(z).^p - lambda.*g
L = 
Lx = diff(L,x)
Lx = 
Ly = diff(L,y)
Ly = 
Lz = diff(L,z)
Lz = 
sol = solve([Lx==0,Ly==0,Lz==0,g==0],[x y z lambda])
Warning: Unable to find explicit solution. For options, see help.
sol = struct with fields:
x: [0x1 sym] y: [0x1 sym] z: [0x1 sym] lambda: [0x1 sym]
sol.x
ans = Empty sym: 0-by-1
sol.y
ans = Empty sym: 0-by-1
sol.z
ans = Empty sym: 0-by-1
  1 件のコメント
Xiao yang
Xiao yang 2024 年 3 月 22 日
I can hand solve this problem, dont know what'wrong the code

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回答 (1 件)

Walter Roberson
Walter Roberson 2024 年 3 月 22 日
移動済み: Walter Roberson 2024 年 3 月 22 日
The 0^n and 0^(m-1) occur because there are not constraints on m and n, so there is the possibility that 0^0 is being generated, and 0^0 is 1 whereas 0^anything_else is 0
syms m n p a x y z lambda real
g = x + y + z -a;
L = (x).^m.*(y).^n.*(z).^p - lambda.*g;
Lx = diff(L,x);
Ly = diff(L,y);
Lz = diff(L,z);
eqns = [Lx==0,Ly==0,Lz==0,g==0];
partial_lambda = solve(eqns(1), lambda, 'returnconditions', true);
%partial_lambda.conditions
eqns2 = subs(eqns(2:end), lambda, partial_lambda.lambda);
partial_x = solve(eqns2(3), x);
eqns3 = subs(eqns2([1:2 4:end]), x, partial_x);
partial_y = solve(eqns3(1), y, 'returnconditions', true);
%partial_y.y
%partial_y.conditions
eqns4 = subs(eqns3(2:end), y, partial_y.y);
syms parameter1 parameter2 real
partial_z1 = subs(solve(eqns4(1,1), z, 'returnconditions', true), sym('x'), parameter1);
partial_z2 = subs(solve(eqns4(2,1), z, 'returnconditions', true), sym('x'), parameter2);
partial_z3 = solve(eqns4(3,1), z, 'returnconditions', true);
%partial_z3.z
%partial_z3.conditions
back_z1 = partial_z1.z;
back_y1 = subs(partial_y.y(1), z, back_z1);
back_x1 = subs(partial_x, {y, z}, {back_y1, back_z1});
back_lambda1 = subs(partial_lambda, {x, y, z}, {back_x1, back_y1, back_z1});
solution1 = [x == back_x1, y == back_y1, z == back_z1, lambda == back_lambda1.lambda]
solution1 = 
back_z2 = partial_z2.z;
back_y2 = subs(partial_y.y(2), z, back_z2);
back_x2 = subs(partial_x, {y, z}, {back_y2, back_z2});
back_lambda2 = subs(partial_lambda, {x, y, z}, {back_x2, back_y2, back_z2});
solution2 = [x == back_x2, y == back_y2, z == back_z2, lambda == back_lambda2.lambda]
solution2 = 
back_z3a = partial_z3.z(1);
back_y3a = subs(partial_y.y(3), z, back_z3a);
back_x3a = subs(partial_x, {y, z}, {back_y3a, back_z3a});
back_lambda3a = subs(partial_lambda, {x, y, z}, {back_x3a, back_y3a, back_z3a});
solution3a = [x == back_x3a, y == back_y3a, z == back_z3a, lambda == back_lambda3a.lambda]
solution3a = 
back_z3b = partial_z3.z(2);
back_y3b = subs(partial_y.y(3), z, back_z3b);
back_x3b = subs(partial_x, {y, z}, {back_y3b, back_z3b});
back_lambda3b = subs(partial_lambda, {x, y, z}, {back_x3b, back_y3b, back_z3b});
solution3b = [x == back_x3b, y == back_y3b, z == back_z3b, lambda == back_lambda3b.lambda]
solution3b = 
back_z3c = partial_z3.z(3);
back_y3c = subs(partial_y.y(3), z, back_z3c);
back_x3c = subs(partial_x, {y, z}, {back_y3c, back_z3c});
back_lambda3c = subs(partial_lambda, {x, y, z}, {back_x3c, back_y3c, back_z3c});
solution3c = [x == back_x3c, y == back_y3c, z == back_z3c, lambda == back_lambda3c.lambda]
solution3c = 
  5 件のコメント
Xiao yang
Xiao yang 2024 年 3 月 28 日
thank you very much
Dyuman Joshi
Dyuman Joshi 2024 年 3 月 29 日
Hello @Xiao yang, if this answer solved your problem, please consider accepting the answer.
Accepting the answer indicates that your problem has been solved (which can be helpful to other people in future) and it awards the volunteer with reputation points for helping you.
You can accept only 1 answer for a question, but you can vote for as many answers as you want. Voting an answer also provides reputation points.

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