converting 3d matrix into a cell array
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Hi,
I have a 3D matrix (1001x 259x 259) and want to convert to a cell array (1x1001) in which each cell array has 259x259 matrix (2D matrix). Could anyone help?
Thanks.
採用された回答
Dyuman Joshi
2024 年 3 月 22 日
@AT_HYZ, change the dimensions and use the above transformation -
abc = rand(1001,259,259);
%Shift dimensions
Mymatrix = shiftdim(abc, 1);
%Check size
size(Mymatrix)
%Use num2cell
Mycell = num2cell(Mymatrix,[1 2]);
size(Mycell)
%Change the size of the cell array as required
Mycell = reshape(Mycell, 1, 1001);
%Check the size of data inside a cell element
size(Mycell{1})
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その他の回答 (1 件)
James Tursa
2024 年 3 月 22 日
編集済み: James Tursa
2024 年 3 月 22 日
x = rand(1001,259,259);
result = arrayfun(@(k)squeeze(x(k,:,:)),1:size(x,1),'uni',false);
size(result)
size(result{1})
But, be advised that for matrix manipulation it might be better to keep this data as a 3D array with dimensions 259x259x1001 (i.e., permute(x,[2 3 1])) so that you can take advantage of the page functions like pagemtimes, pagemldivide, etc.
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