when char(65) then A.

 but when we define A='5', then char(5) can not be the result A. how can we get this value?

Answer 1

[Ilham Hardy]

Just guessing,

>> char(65)

ans =

A

>> double('A')

ans =

      65

Answer 2

[Star Strider]

You have defined ‘A’ as a string, so it will remain so. If you want to find the numeric value (5) you assigned to ‘A’, you would have to use the str2num or similar funcitons:

A = '5';
a = str2num(A)

produces:

a =

       5.0000e+000