Adjusting a Sawtooth Graph and getting spectrum
5 ビュー (過去 30 日間)
古いコメントを表示
I am trying to graph a traingle wave with a width of 8000pi (4000pi each way from 0) and get its spectrum. This is what I have but can't get figure 1 to look right. I am unsure what I am doing wrong, my best guess would be I need to change either T or the first variable in sawtooth but doing that keeps making it worse so I'm not sure. Thank you for your time!
T = 10*50;
fs = 2000;
t = 0:1/fs:T-1/fs;
x = sawtooth(pi*4000*t,1/2);
figure(1)
plot(t,x)
grid on
figure(2)
pspectrum(x,fs,'Leakage',0.91)
0 件のコメント
採用された回答
Paul
2024 年 2 月 25 日
編集済み: Paul
2024 年 2 月 25 日
Do you want a triangle or a sawtooth? Assuming the former as stated in the question, use tripuls
%T = 10*50;
fs = 2000;
t = -4000*pi:1/fs:4000*pi;
numel(t) % lots of data points
x = tripuls(t,pi*8000,0);
figure(1)
plot(t,x)
xline(4000*pi);xline(-4000*pi);
3 件のコメント
Paul
2024 年 2 月 25 日
The time vector already spans -4000*pi to 4000*pi. I added some lines to the plot to make that clear.
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Time Series Events についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!