How do I solve this ODE system where there exists derivatives in both sides?

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Arda Senyurek
Arda Senyurek 2024 年 1 月 6 日
編集済み: Sam Chak 2024 年 1 月 6 日
The system of ODE is the following equation.
Second equation is no of a problem but first and the third one is the problematic for me. Because I can't get them in the form that is similar when using ode45. That is, I can't seperate the derivatives because and are coupled.
Any help is appreciated. Thanks!

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David Goodmanson
David Goodmanson 2024 年 1 月 6 日
編集済み: David Goodmanson 2024 年 1 月 6 日
Hi Arda,
These two equations are of the form
p' Jxx - r' Jxz = f(...) where ... = p,q,r,J,J,M,M (a bunch of known stuff)
-p' Jxz + r' Jzz = g(...) where ... = a bunch of other known stuff
in matrix form this is
[Jxx -Jxz; -Jxz Jzz]*[p'; r'] = [f; g];
where the semicolons produce a 2x2 matrix and two 2x1 column vectors. This is solved by left divide.
[p'; r'] = [Jxx -Jxz; -Jxz Jzz]\[f; g]
which works fine for calculation, or if you prefer you can use the tedious longhand version
p' = (Jzz*f + Jxz*g) / (Jxx*Jzz - Jxz^2)
r' = (Jxz*f + Jxx*g) / (Jxx*Jzz - Jxz^2)
  3 件のコメント
Sam Chak
Sam Chak 2024 年 1 月 6 日
編集済み: Sam Chak 2024 年 1 月 6 日
This is Euler's equations of rotational motion for a rigid body. Basically, David's approach allows the decoupling of the equations of motion into two separate state equations.
In MATLAB, the syntax to perform matrix left division may be given by:
J = [Jxx -Jxz;
-Jxz Jzz];
M = [Mx + fx;
Mz + fz];
dwdt(1:2) = J\M;
Arda Senyurek
Arda Senyurek 2024 年 1 月 6 日
No, I see it now, but I couldn't before asking. That's what I'm referring to in my reply. Thanks!

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その他の回答 (1 件)

Alan Stevens
Alan Stevens 2024 年 1 月 6 日
You can separate the terms as follows:

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