Retain rows and columns depending on the values of an array

Hi,

For example I have the square matrix:

A = [3 5 7 1 2; 2 4 3 1 5; 2 6 1 6 6; 4 7 5 1 1; 2 0 1 5 2]

Assuming I have the vector B, B = [1, 4, 5]

How do I get this output: A = [ 3 7 2; 2 1 6; 2 1 2]

Essentially it means A(2,:) = [], A(3,:) = [], A(:,2) = [], and A(:,3) = []. I was wondering if there is a more elegant way of doing this?

Answer 1

[Voss]

A = [3 5 7 1 2; 2 4 3 1 5; 2 6 1 6 6; 4 7 5 1 1; 2 0 1 5 2];
B = [1, 3, 5];

A = A(B,B)

A = 3×3

3 7 2 2 1 6 2 1 2

(The example suggests B is [1 3 5], not [1 4 5].)

[Allan Paolo]

Ah yes. Thank you very very much!

[Voss]

You're welcome!