Why my user-defined matlab function returns NaN?

2 ビュー (過去 30 日間)
Ramiro
Ramiro 2023 年 12 月 14 日
移動済み: Voss 2023 年 12 月 14 日
I wrote a matlab function but when the input argument vector has only one element, it returns NaN. I checked my code and I think everything is OK.
The W argument is a n x 1 vector or a 1 x n vector of weights that sum 1. However, when W = 1, the function returns NaN.
I think it is a bug of my Matlab version (2023b for Mac Intel).
Thanks in advance for your help.
Ramiro
W = 1;
orn = Orness(W)
orn = 1
function orn = Orness(W)
nW = numel(W);
if nW >= 2
orn = zeros(nW,1);
for j = 1:nW
orn(j) = ((nW-j)/(nW-1))*W(j);
end
orn = sum(orn);
elseif nW == 1
orn = 1;
end
end
  1 件のコメント
Torsten
Torsten 2023 年 12 月 14 日
I cannot reproduce the behaviour you describe (see above).

サインインしてコメントする。

採用された回答

Ramiro
Ramiro 2023 年 12 月 14 日
移動済み: Voss 2023 年 12 月 14 日
Hi, thank you for the command. My path have two Orness functions (one very old). The script is using that function instead of the new one.
So I made the mistake. I renamed the new function and the problem is fixed.
This solved my issue.
Regards
Ramiro

その他の回答 (0 件)

タグ

製品


リリース

R2023b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by