フィルターのクリア

convert the table to matrix

58 ビュー (過去 30 日間)
Mario
Mario 2023 年 12 月 5 日
回答済み: Walter Roberson 2023 年 12 月 5 日
Hi,
I used the below command and it read the dat files as a table (1x1500 cell) and each cell include (65536x4 table)
for k = 1:1500
myfilename = sprintf('Vec%05d.dat', k);
mydata{k} = readtable(myfilename);
end
then I tried to convert the table to matrix, but it doesn't work, could you please correct it to me?
for k = 1:1500
mydata1(:,:,k)= table2array(mydata{:,k})
end
my aim is to get a matrix of mydata1 with size 256x256x1500
thanks in advance
  3 件のコメント
Walter Roberson
Walter Roberson 2023 年 12 月 5 日
Do you need the intermediate tables to be stored for some reason, or do you just need the final array?
Is there a reason you are using readtable() instead of readmatrix() ?
Mohamed
Mohamed 2023 年 12 月 5 日
No I don't want to store the tables , I need the final array

サインインしてコメントする。

採用された回答

Walter Roberson
Walter Roberson 2023 年 12 月 5 日
N = 1500;
%we proceed in two steps.
%we read one array
for k = 1
myfilename = sprintf('Vec%05d.dat', k);
mydata1 = readmatrix(myfilename);
end
%and that tells us how much data is in each file.
%Now we extend array efficiently. Doing a single
%array extension like this is a heck of a lot faster
%than growing the array each iteration
mydata1(end,end,N) = 0;
%now read the rest of the files
for k = 2:N
myfilename = sprintf('Vec%05d.dat', k);
thisdata = readmatrix(myfilename);
mydata1(:,:,k) = thisdata;
end
%we have all of the data
%reshape it.
%we assume 256 rows but we do not assume columns
mydata1 = reshape(mydata1, 256, [], size(mydat1,2), size(mydata1,3));

その他の回答 (1 件)

Sulaymon Eshkabilov
Sulaymon Eshkabilov 2023 年 12 月 5 日
I believe as Madhan pinpointed that you data size should be 256x256x4x1500. Here is the final code:
for k = 1:1500
myfilename = sprintf('Vec%05d.dat', k);
mydata{k} = readtable(myfilename);
mydata1(:,:,k)= table2array(mydata{:,k})
end
%% Final conversion after collecting all data from the files into an ARRAY
MY_data_OK = reshape(MY_data, [256, 256, 4, 1500]);
  1 件のコメント
Mohamed
Mohamed 2023 年 12 月 5 日
Actually, I am not sure that: mydata1(:,:,k)=table2array(mydata{:,k})
This command worked for a day without stopping. So I could you please tell me where is the mistake because I think it is just a loop

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeLogical についてさらに検索

製品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by