Adding more values to an array every loop

Im trying to add a new value to y, as the loop progresses, to create an array, in this instance y=[1,3,5,7]. Meanwhile, all I get is the final number of that array, y=7 as a result. I know that this happens because the values are not added one by one but are all added spontaneously, so the seven fits the criteria for the "if" , but I dont have a clue on how to fix this.

Any help or tip would be appreciated, I have been stuck with this for hours and I cant find any solution online...

clear
y=0;
for k=1:2:10;
   x=[1:10];
    
    if sum(y.^2)>30
        break
    end
    y=x(k);
end

disp(y)

Answer 1

[Matt J]

One possibility,

y=nan(1,100);
s=0;
for k=1:numel(y)
    
    y(k)=2*k-1;
    s=s+y(k).^2;
    
    if s>40, 
        y=y(1:k);
        break; 
    end
    
end

y

y = 1×4

1 3 5 7

[Odysseas]

Thanks, this will do! I will try to compare it to my attempts to find other possible solutions.