Generate specific binary combination

5 ビュー (過去 30 日間)
Khoa Tran
Khoa Tran 2023 年 11 月 30 日
コメント済み: Khoa Tran 2023 年 11 月 30 日
Hi guys,
I am working with binary combinations and encountering a problem with memory as the N value gets bigger. I am using this function to create my binary combinations array:
N = 4;
dec2bin(0:2^N-1) - '0'
I need to iterate each combination in the array in my calculation (i.e., iterating each row of the array at a time). Is there a way that we can generate a specific combination without having to create the whole array beforehand and use only one row at a time?
For example, 7th row in the array is [0 1 1 0]. I want to create [0 1 1 0], do the calculation, then continue to 8th row and so on.
Your inputs are much appreciated.

採用された回答

Walter Roberson
Walter Roberson 2023 年 11 月 30 日
N = 4;
for K = 0 : 2^N - 1
thiscombo = dec2bin(K,N);
stuff
end
  1 件のコメント
Khoa Tran
Khoa Tran 2023 年 11 月 30 日
Thanks @Walter Roberson. This is just what I need.

サインインしてコメントする。

その他の回答 (1 件)

Chunru
Chunru 2023 年 11 月 30 日
You can put the dec2bin inside the loop so it won't be a big array.
N = 4;
for i=0:2^N-1
c = dec2bin(i, N) - '0'
end
c = 1×4
0 0 0 0
c = 1×4
0 0 0 1
c = 1×4
0 0 1 0
c = 1×4
0 0 1 1
c = 1×4
0 1 0 0
c = 1×4
0 1 0 1
c = 1×4
0 1 1 0
c = 1×4
0 1 1 1
c = 1×4
1 0 0 0
c = 1×4
1 0 0 1
c = 1×4
1 0 1 0
c = 1×4
1 0 1 1
c = 1×4
1 1 0 0
c = 1×4
1 1 0 1
c = 1×4
1 1 1 0
c = 1×4
1 1 1 1
  1 件のコメント
Khoa Tran
Khoa Tran 2023 年 11 月 30 日
Thanks @Chunru. A simple and effective solution.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeLoops and Conditional Statements についてさらに検索

製品


リリース

R2023b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by