Why the distribution along spatial axis x changes tremendously even by increasing only one step size?
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I study the Schnakenberg-Turing model on a static 1D domain:
% The PDEs are
% D(u1)/Dt = 1*D^2(u1)/Dx^2 + 70(0.2-u1 + u1^2*u2)
% D(u2)/Dt = 100*D^2(u2)/Dx^2 + 70(0.5 - u1^2*u2)
%
% The initial condition is u1(x,0) = 0 and u2(x,0) = 0 for 0 <= x <= 1.
% The left boundary condition is D(u1)/Dx = 0, D(u2)/Dx = 0.
% The right boundary condition is D(u1)/Dx = 0, D(u2)/Dx = 0:
%
L = 1;
maxt = 10;
m = 0;
x = linspace(0,1,100);
% x = linspace(0,1,101);
% IF the no. of points of x is changed from 100 to 101, the result changes tremendously. See the following figures.
% Which is the correct?
t = linspace(0,10,101);
sol = pdepe(m,@pdex4pde,@pdex4ic,@pdex4bc,x,t);
u1 = sol(:,:,1);
u2 = sol(:,:,2);
% Plotting the the final distribution of u1 at t=10.
figure(1)
plot(x,u1(end,:))
title('Final distribution of u1(x,t)')
% --------------------------------------------------------------------------
function [c,f,s] = pdex4pde(x,t,u,DuDx)
a = 0.2;
c = [1; 1];
f = [1; 100] .* DuDx;
s = [70*(a-u(1)+u(1)^2*u(2));
70*(0.5-u(1)^2*u(2))];
% --------------------------------------------------------------------------
function u0 = pdex4ic(x)
u0 = [0; 0];
% --------------------------------------------------------------------------
function [pl,ql,pr,qr] = pdex4bc(xl,ul,xr,ur,t)
pl = [0; 0];
ql = [1; 1];
pr = [0; 0];
qr = [1; 1];
1 件のコメント
Torsten
2023 年 11 月 4 日
Isn't this behaviour typical for the model ? When I googled "Schnakenberg-Turing model", all the hits were related to stability analysis.
回答 (1 件)
SOUMNATH PAUL
2023 年 12 月 29 日
Hi,
To my understanding the tremendous change in the distribution along the spatial axis x when increasing the step size is likely due to the following points:
- Small changes in discretization can lead to different numerical instabilities in nonlinear PDEs.
- Turing patterns are sensitive to spatial discretization, which affects the represented wavelengths and modes.
- A finer or coarser grid changes the discretization error, influencing the solution's accuracy.
- The accuracy of Neumann boundary conditions representation can vary with grid spacing.
To determine which result is more accurate kindly perform a convergence test, check for stability and physical validity, ensure mesh independence, and consider using different numerical methods for verification.
Hope it helps!
Regards,
Soumnath
0 件のコメント
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