Transforming a row (inside a matrix) with equal numbers into a row with only one number
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I have amatrix of the following type:
in = [228 228 228
231 231 231
183 183 183
157 157 157
168 168 168];
I need to know if the 3 columns of each row are equal and, if they are, get an Rx1 matrix at the end:
out = [228; 231; 183; 157; 168];
If they are not, keep the initial matrix Rx3 ('in' matrix) and tell me in which row the values of the three columns are not the same.
in_new = [228 228 228
231 231 231
183 200 183
157 157 157
168 168 200];
out_new = [3;5];
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Dyuman Joshi
2023 年 11 月 1 日
編集済み: Dyuman Joshi
2023 年 11 月 1 日
in1 = [228 228 228
231 231 231
183 183 183
157 157 157
168 168 168];
[a1, b1] = transform(in1)
in2 = [228 228 228
231 231 231
183 200 183
157 157 157
168 168 200];
[a2, b2] = transform(in2)
function [out, out_new] = transform(in)
idx = all(~diff(in, [], 2), 2);
if all(idx)
out = in(:,1);
out_new = [];
else
out = in;
out_new = find(~idx);
end
end
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