How to plot this function with 2 variables?

Hello, I’m having a hard time plotting z2(t). I keep getting the error “input must be a function or functions of a single variable”. I’m not sure how to properly define “u”.

2 件のコメント

Marisa
Marisa 2023 年 10 月 30 日
Dyuman Joshi
Dyuman Joshi 2023 年 10 月 30 日
移動済み: Dyuman Joshi 2023 年 10 月 30 日
As you are using fplot, the expected input is a function handle.
And the syntax to define a function handle is
name_of_handle = @(independent_variables) relation_or_expression_of_independent_variables
%For the first example, it translates to
z1 = @(t) exp(t);
Refer to these links for more information -

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回答 (1 件)

Voss
Voss 2023 年 10 月 30 日

0 投票

t = -2:0.01:2;
z1 = exp(t);
z2 = 2*(t+1 >= 0);
z3 = 0.5*sin(7*t);
hold on
grid on
plot(t,z1,'-','LineWidth',2)
plot(t,z2,':','LineWidth',2)
plot(t,z3,'--','LineWidth',2)
xlabel('t')
ylabel('z')
legend("z"+[1 2 3])
ylim([-1 8])

9 件のコメント

Dyuman Joshi
Dyuman Joshi 2023 年 10 月 30 日
Just a note -
z2 = 2*(t+1 >= 0);
">= 0" is not mentioned in the question
Voss
Voss 2023 年 10 月 30 日
I interpret u(t) to be the unit step function.
Dyuman Joshi
Dyuman Joshi 2023 年 10 月 30 日
Alright.
Marisa
Marisa 2023 年 10 月 30 日
Thank you, The original question wants me to plot z2(t)=2u(t+1), I’m not sure how to plot this since it also involves “u”
Sam Chak
Sam Chak 2023 年 10 月 30 日
The signal u(·) in the question most likely refers to the unit step function, which can be represented by the Heaviside function.
t = -2:0.001:2;
z2 = 2*heaviside(t + 1);
plot(t,z2,':','LineWidth',2), grid on
xlabel('t')
ylabel('z')
ylim([-1 8])
Marisa
Marisa 2023 年 10 月 30 日
Okay the example mentioned Heaviside but I tried to use that and wasn’t getting it right. This makes sense! This worked, thank you so much! I was just putting Heaviside in incorrectly.
Voss
Voss 2023 年 10 月 30 日
@Marisa: Or if you don't have the Symbolic Math Toolbox, you can write down what the unit step function is in your definition of z2, as I have done in my answer.
Sam Chak
Sam Chak 2023 年 10 月 30 日
Good to hear that, @Marisa. 👍
Sam Chak
Sam Chak 2023 年 10 月 30 日
In the mathematical representation of linear physical systems (later in your course), you may encounter the state-space equation, . But this is not the unit step function. Please keep that in mind.

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