Method to get as large and few as number boxes

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Pete sherer
Pete sherer 2023 年 10 月 18 日
コメント済み: Pete sherer 2023 年 10 月 20 日
oriLat=[48.3860120000000;49.3686790000000;48.0145280000000;46.6825390000000;47.4787370000000;46.5073030000000;46.5176190000000;44.9243550000000;45.2906840000000;42.3015220000000;41.9182910000000;44.6990460000000;45.7893010000000;45.2741950000000;43.7351650000000;43.8312240000000;41.7326470000000;41.3863160000000;44.9774490000000;45.2345130000000;47.3537330000000;44.8174190000000;43.3218860000000;41.5511100000000;39.4791860000000;37.8949860000000;37.1004480000000;39.4531150000000;38.0365030000000;38.6352170000000;35.2258250000000;31.1253830000000;26.7715300000000;24.8661310000000;29.9185130000000;30.6849560000000;30.0184100000000;28.9338120000000;29.4307800000000;27.9083070000000;25.8403780000000;29.7380790000000;28.9821380000000;31.7520090000000;31.3322390000000;34.5540170000000;40.2609740000000;46.2591090000000;48.3860120000000];
oriLon=[-124.725839000000;-94.9521110000000;-89.4892260000000;-91.9618890000000;-87.9292690000000;-87.3667670000000;-84.1179250000000;-87.8434330000000;-86.9777800000000;-87.8347690000000;-86.5978990000000;-86.2484740000000;-84.7727650000000;-83.3851040000000;-83.9477400000000;-82.6336410000000;-83.4538320000000;-82.4605990000000;-74.9927560000000;-70.8444300000000;-68.2697100000000;-66.9498950000000;-70.5538540000000;-69.9649820000000;-75.5930680000000;-75.3386230000000;-75.9796080000000;-76.0123120000000;-76.3220930000000;-77.2467040000000;-75.5336270000000;-81.4020960000000;-80.0321200000000;-80.6511890000000;-83.6792190000000;-88.0083960000000;-89.8450650000000;-89.4009660000000;-94.6703890000000;-97.0033250000000;-97.4226360000000;-101.400636000000;-103.281190000000;-106.417940000000;-111.074825000000;-120.622575000000;-124.363414000000;-123.547659000000;-124.725839000000];
N = 100 ; % can be varied
lon = linspace(min(oriLon),max(oriLon),N) ;
lat = linspace(min(oriLat),max(oriLat),N) ;
%
[Lon,Lat] = meshgrid(lon,lat) ;
% pick points lying inside the given region
idx = inpolygon(Lon(:), Lat(:),oriLon, oriLat) ;
Lon(~idx) = NaN ; Lat(~idx) = NaN ;
plot( oriLon, oriLat, 'b')
hold on
plot(Lon,Lat,'.r')
The above gives me multiple uniform grids fitting within a polygon. From above I would like to reduce number of recangulars by replacing them with larger grids/ boxes. Each box could have different size. Usually near the edge, the size would be smaller.
What would be the approach to go about this?
  6 件のコメント
Steven Lord
Steven Lord 2023 年 10 月 19 日
What's your ultimate goal in creating these boxes? What are you hoping to use these boxes to do?
Do you require these boxes to stay strictly within the boundaries of the shape or is some coverage of the area outside the shape acceptable?
Are the boxes required to be rectangles? Are general quadrilaterals allowed? Are polygons with other number of sides allowed (triangulate the area, tile it with hexagons, cover it with N-sided polygons for large N that approximate circles, etc.)? Are arbitrarily shaped regions allowed (jigsaw puzzle pieces or electoral district drawing / gerrymandering)?
What's your success criteria? What's most important from the list below?
  • maximum amount of coverage / minimize uncovered area
  • minimize amount of area outside the shape that is covered (if covering outside the area is allowed)
  • minimize number of boxes
  • maximize box size
Walter Roberson
Walter Roberson 2023 年 10 月 19 日
For example, imagine that you have a 2 x 10 area in which the top right is not available. Would you want that covered by a (1 x 9 + 1 x 10) or as a (2 x 9 + 1 x 1) ? Or as a 2 x 10 with it being "forgiven" that it goes outside the boundary?

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採用された回答

Fabio Freschi
Fabio Freschi 2023 年 10 月 20 日
編集済み: Fabio Freschi 2023 年 10 月 20 日
The following attempt is far from being a perfect answer to your question. All perplexities of @Walter Roberson are also mine, so I have drastically simplified the problem assuming
  1. the use of square boxes instead of rectangular ones
  2. the possibility of randomly starting the creation of new boxes
  3. the number of boxes is not minimum
If you are optimistic and benevolent, the solution found can be said to be "sub-optimal", but I think it's a starting point you can use to find a better solution.
clear variables, close all
% perimeter
oriLat = [48.3860120000000;49.3686790000000;48.0145280000000;46.6825390000000;47.4787370000000;46.5073030000000;46.5176190000000;44.9243550000000;45.2906840000000;42.3015220000000;41.9182910000000;44.6990460000000;45.7893010000000;45.2741950000000;43.7351650000000;43.8312240000000;41.7326470000000;41.3863160000000;44.9774490000000;45.2345130000000;47.3537330000000;44.8174190000000;43.3218860000000;41.5511100000000;39.4791860000000;37.8949860000000;37.1004480000000;39.4531150000000;38.0365030000000;38.6352170000000;35.2258250000000;31.1253830000000;26.7715300000000;24.8661310000000;29.9185130000000;30.6849560000000;30.0184100000000;28.9338120000000;29.4307800000000;27.9083070000000;25.8403780000000;29.7380790000000;28.9821380000000;31.7520090000000;31.3322390000000;34.5540170000000;40.2609740000000;46.2591090000000;48.3860120000000];
oriLon = [-124.725839000000;-94.9521110000000;-89.4892260000000;-91.9618890000000;-87.9292690000000;-87.3667670000000;-84.1179250000000;-87.8434330000000;-86.9777800000000;-87.8347690000000;-86.5978990000000;-86.2484740000000;-84.7727650000000;-83.3851040000000;-83.9477400000000;-82.6336410000000;-83.4538320000000;-82.4605990000000;-74.9927560000000;-70.8444300000000;-68.2697100000000;-66.9498950000000;-70.5538540000000;-69.9649820000000;-75.5930680000000;-75.3386230000000;-75.9796080000000;-76.0123120000000;-76.3220930000000;-77.2467040000000;-75.5336270000000;-81.4020960000000;-80.0321200000000;-80.6511890000000;-83.6792190000000;-88.0083960000000;-89.8450650000000;-89.4009660000000;-94.6703890000000;-97.0033250000000;-97.4226360000000;-101.400636000000;-103.281190000000;-106.417940000000;-111.074825000000;-120.622575000000;-124.363414000000;-123.547659000000;-124.725839000000];
% discretization size
N1 = 80;
N2 = 60;
x = linspace(min(oriLon),max(oriLon),N1) ;
y = linspace(min(oriLat),max(oriLat),N2) ;
% create meshgrid
[x,y] = meshgrid(x,y) ;
% pick points lying inside the given region
idx = inpolygon(x(:),y(:),oriLon, oriLat);
% reshape idx
idx = reshape(idx,size(x));
% coloring matrix (-1: out, 0: in & never touched, >0 in & touched)
col = zeros(size(idx));
col(~idx) = -NaN;
% plot
h = figure; hold on
plot(oriLon, oriLat, 'b')
% rng(2);
for icol = 1:N1*N2
% select a random point to start
idx0 = find(col(:) == 0);
if isempty(idx0)
break
end
[i0,j0] = ind2sub(size(col),idx0(randi(length(idx0))));
% move north-est
chk = true;
k_ne = 0;
while chk
k_ne = k_ne+1;
if any(any(col(i0:i0+k_ne,j0:j0+k_ne) ~= 0))
k_ne = k_ne-1;
% col(i0:i0+k_ne,j0:j0+k_ne) = icol;
chk = false;
end
end
% move south-west
chk = true;
k_sw = 0;
while chk
k_sw = k_sw+1;
if any(any(col(i0-k_sw:i0+k_ne,j0-k_sw:j0+k_ne) ~= 0))
k_sw = k_sw-1;
col(i0-k_sw:i0+k_ne,j0-k_sw:j0+k_ne) = icol;
chk = false;
end
end
% plot colored points
scatter(reshape(x(i0-k_sw:i0+k_ne,j0-k_sw:j0+k_ne),[],1),...
reshape(y(i0-k_sw:i0+k_ne,j0-k_sw:j0+k_ne),[],1),...
15,reshape(col(i0-k_sw:i0+k_ne,j0-k_sw:j0+k_ne),[],1),'filled');
if k_ne+k_sw > 1
xl = [x(i0-k_sw,j0-k_sw)
x(i0+k_ne,j0-k_sw)
x(i0+k_ne,j0+k_ne)
x(i0-k_sw,j0+k_ne)
x(i0-k_sw,j0-k_sw)];
yl = [y(i0-k_sw,j0-k_sw)
y(i0+k_ne,j0-k_sw)
y(i0+k_ne,j0+k_ne)
y(i0-k_sw,j0+k_ne)
y(i0-k_sw,j0-k_sw)];
plot(xl,yl,'-','LineWidth',2);
end
end
fprintf('final number of boxes: %d\n',icol)
final number of boxes: 335
Hope it helps
  3 件のコメント
Fabio Freschi
Fabio Freschi 2023 年 10 月 20 日
編集済み: Fabio Freschi 2023 年 10 月 20 日
I added the possibility of creation rectangles from squares, as suggested in my provious comment, with some cleanup and small improvements: the number of rectangles is now reduced to 25%-30% with respect to the previous method.
clear variables, close all
% perimeter
oriLat = [48.3860120000000;49.3686790000000;48.0145280000000;46.6825390000000;47.4787370000000;46.5073030000000;46.5176190000000;44.9243550000000;45.2906840000000;42.3015220000000;41.9182910000000;44.6990460000000;45.7893010000000;45.2741950000000;43.7351650000000;43.8312240000000;41.7326470000000;41.3863160000000;44.9774490000000;45.2345130000000;47.3537330000000;44.8174190000000;43.3218860000000;41.5511100000000;39.4791860000000;37.8949860000000;37.1004480000000;39.4531150000000;38.0365030000000;38.6352170000000;35.2258250000000;31.1253830000000;26.7715300000000;24.8661310000000;29.9185130000000;30.6849560000000;30.0184100000000;28.9338120000000;29.4307800000000;27.9083070000000;25.8403780000000;29.7380790000000;28.9821380000000;31.7520090000000;31.3322390000000;34.5540170000000;40.2609740000000;46.2591090000000;48.3860120000000];
oriLon = [-124.725839000000;-94.9521110000000;-89.4892260000000;-91.9618890000000;-87.9292690000000;-87.3667670000000;-84.1179250000000;-87.8434330000000;-86.9777800000000;-87.8347690000000;-86.5978990000000;-86.2484740000000;-84.7727650000000;-83.3851040000000;-83.9477400000000;-82.6336410000000;-83.4538320000000;-82.4605990000000;-74.9927560000000;-70.8444300000000;-68.2697100000000;-66.9498950000000;-70.5538540000000;-69.9649820000000;-75.5930680000000;-75.3386230000000;-75.9796080000000;-76.0123120000000;-76.3220930000000;-77.2467040000000;-75.5336270000000;-81.4020960000000;-80.0321200000000;-80.6511890000000;-83.6792190000000;-88.0083960000000;-89.8450650000000;-89.4009660000000;-94.6703890000000;-97.0033250000000;-97.4226360000000;-101.400636000000;-103.281190000000;-106.417940000000;-111.074825000000;-120.622575000000;-124.363414000000;-123.547659000000;-124.725839000000];
% discretization size
N1 = 80;
N2 = 60;
x = linspace(min(oriLon),max(oriLon),N1) ;
y = linspace(min(oriLat),max(oriLat),N2) ;
% create meshgrid
[x,y] = meshgrid(x,y) ;
% pick points lying inside the given region
idx = inpolygon(x(:),y(:),oriLon, oriLat);
% reshape idx
idx = reshape(idx,size(x));
% coloring matrix (-1: out, 0: in & never touched, >0 in & touched)
col = zeros(size(idx));
col(~idx) = -NaN;
% plot
h = figure; hold on
plot(oriLon, oriLat, 'b')
rng(2);
for icol = 1:N1*N2
% select a random point to start
idx0 = find(col(:) == 0);
if isempty(idx0)
break
end
[i0,j0] = ind2sub(size(col),idx0(randi(length(idx0))));
% initial values
k_n = 0;
k_e = 0;
k_s = 0;
k_w = 0;
% move north-est
chk = true;
while chk
k_n = k_n+1;
k_e = k_e+1;
if any(col(i0:i0+k_e,j0:j0+k_n) ~= 0,'all')
k_n = k_n-1;
k_e = k_e-1;
chk = false;
end
end
% try only north
chk = true;
while chk
k_n = k_n+1;
if any(col(i0:i0+k_e,j0:j0+k_n) ~= 0,'all')
k_n = k_n-1;
chk = false;
end
end
% try only east
chk = true;
while chk
k_e = k_e+1;
if any(col(i0:i0+k_e,j0:j0+k_n) ~= 0,'all')
k_e = k_e-1;
chk = false;
end
end
% move south-west
chk = true;
while chk
k_s = k_s+1;
k_w = k_w+1;
if any(col(i0-k_w:i0+k_e,j0-k_s:j0+k_n) ~= 0,'all')
k_s = k_s-1;
k_w = k_w-1;
chk = false;
end
end
% try only south
chk = true;
while chk
k_s = k_s+1;
if any(col(i0-k_w:i0+k_e,j0-k_s:j0+k_n) ~= 0,'all')
k_s = k_s-1;
chk = false;
end
end
% try only west
chk = true;
while chk
k_w = k_w+1;
if any(col(i0-k_w:i0+k_e,j0-k_s:j0+k_n) ~= 0,'all')
k_w = k_w-1;
chk = false;
end
end
% set new box id
col(i0-k_w:i0+k_e,j0-k_s:j0+k_n) = icol;
% plot colored points
scatter(reshape(x(i0-k_w:i0+k_e,j0-k_s:j0+k_n),[],1),...
reshape(y(i0-k_w:i0+k_e,j0-k_s:j0+k_n),[],1),...
15,reshape(col(i0-k_w:i0+k_e,j0-k_s:j0+k_n),[],1),'filled');
if k_n+k_s > 0 && k_e+k_w > 0
xl = [x(i0-k_w,j0-k_s)
x(i0+k_e,j0-k_s)
x(i0+k_e,j0+k_n)
x(i0-k_w,j0+k_n)
x(i0-k_w,j0-k_s)];
yl = [y(i0-k_w,j0-k_s)
y(i0+k_e,j0-k_s)
y(i0+k_e,j0+k_n)
y(i0-k_w,j0+k_n)
y(i0-k_w,j0-k_s)];
plot(xl,yl,'-','LineWidth',2);
end
end
fprintf('final number of boxes: %d\n',icol)
final number of boxes: 91
Pete sherer
Pete sherer 2023 年 10 月 20 日
Hi All,
Thans very much for the suggestions and thought processes. Yes the box could go over the coundary area. I will look at the code Fabio's provided and fine-tuning it from there.
Thanks again for all of the helpful tips.

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