函数或变量 'poly2str' 无法识别,如何导入poly2str?

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Ran
Ran 2023 年 10 月 12 日
コメント済み: 慧敏 2024 年 5 月 10 日
x=-2*pi:pi/2:2*pi;
y=[1,0,-1,0,1,0,-1,0,1];
p2=polyfit(x,y,2);
p3=polyfit(x,y,3);
p4=polyfit(x,y,4);
p6=polyfit(x,y,6);
disp('二次拟合函数'),f2=poly2str(p2,'x');
disp('三次拟合函数'),f3=poly2str(p3,'x');
disp('四次拟合函数'),f4=poly2str(p4,'x');
disp('七次拟合函数'),f6=poly2str(p6,'x');
x1=-2*pi:pi/10:2*pi;
y2=polyval(p2,x1);
y3=polyval(p3,x1);
y4=polyval(p4,x1);
y6=polyval(p6,x1);
yy=cos(x1);
plot(x,y,x1,y2,'-b',x1,y3,'-.r',x1,y4,'*c',x1,y6,'.g',x1,yy);

採用された回答

Yash
Yash 2023 年 10 月 18 日
Hi Ran,
我会用英语回答
I understand that you want to use "poly2str" function to return polynomial as string. I tried reproducing the error "Unrecognized function or variable 'poly2str'" on my end. However, I didn't encounter any error. Consider running the following command in the MATLAB command window to check if "poly2str.m" is present on the root path:
>> which poly2str -all
If "poly2str.m" is not found by "which", then consider running the following command in the MATLAB command window to refresh function and file system path cache:
>> rehash toolboxcache
If "poly2str.m" is still not found by "which", then verify if "Control System" toolbox is installed or not. Refer here for more information on installing a toolbox: https://www.mathworks.com/matlabcentral/answers/101885-how-do-i-install-additional-toolboxes-into-an-existing-installation-of-matlab
Alternatively, consider using the function "poly2sym" to create symbolic polynomial from vector of coefficients. Refer here for more information on "poly2sym" function: https://www.mathworks.com/help/releases/R2023a/symbolic/sym.poly2sym.html
>> p = poly2sym([0.75, -0.5, 0.25])
p =
(3*x^2)/4 - x/2 + 1/4
I hope this helps!
  2 件のコメント
Ran
Ran 2023 年 10 月 19 日
Thank you very much!It helps me a lot and solves my homework i have been struggling with.
慧敏
慧敏 2024 年 5 月 10 日
请问最后是怎么解决的?

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