フィルターのクリア

How to Integrate these data ?

1 回表示 (過去 30 日間)
farzad
farzad 2015 年 4 月 14 日
編集済み: pfb 2015 年 4 月 14 日
Hi All
I have a Diagram of Data x-y like this :
and the integration should look like :
having the Data of the first diagram as :
x=[0: 0.06] , you choose the step
and y = [-0.062847398, -0.057017095, -0.048434094, -0.03892462, -0.030365732, -0.023723144, -0.019435892, -0.017256826, -0.01674607, -0.01734093, -0.018578755, -0.020101786, -0.021674287, -0.023155192, -0.024468152, -0.025585016, -0.026502747, -0.027236393, -0.027807428, -0.02824128, -0.028562468, -0.028794073, -0.028956106, -0.029065736, -0.029136971, -0.029181112, -0.0292069, -0.029220911, -0.029227789, -0.029230507, -0.029230507, -0.029227789, -0.029220911, -0.0292069, -0.029181112, -0.029136971, -0.029065736, -0.028956106, -0.028794073, -0.028562468, -0.02824128, -0.027807429, -0.027236391, -0.026502745, -0.025585016, -0.024468152, -0.023155192, -0.021674288, -0.020101786, -0.018578757, -0.01734093, -0.01674607, -0.017256826, -0.019435894, -0.023723146, -0.030365737, -0.038924627, -0.048434086, -0.057017088, -0.062847398]
How can I integrate on these data so I will have more or less the same final amount of the integration that you see on the second graph : -2e-3 ? I know that my data are not precisely similar as the first graph , but I just would like to know how to do the integration with these data ? thank you

採用された回答

pfb
pfb 2015 年 4 月 14 日
編集済み: pfb 2015 年 4 月 14 日
You could use "cumptrapz". For that you'll need to provide both x and y.
In this respect, what do you mean "you choose the step"? If there is "a step" it will be something like the integration integral over the number of sampled points...
  7 件のコメント
farzad
farzad 2015 年 4 月 14 日
Should I only write :
cumtrapz(y)
??????????
pfb
pfb 2015 年 4 月 14 日
編集済み: pfb 2015 年 4 月 14 日
You could read the documentation for cumtrapz, to begin with. Do you want to learn how to do things, or are you just having other people solve your homeworks?????????
The documentation pops up when you type "help cumtrapz" or "doc cumtrapz".
In general the function needs to know the abscissae as well, as I mention above. The result depends on that too. Therefore it should be
I = cumtrapz(x,y);
I think you know the abscissae, otherwise how could you plot the figure in the first place?
If you just need the integral on the whole interval (as opposed to the second plot) you could use trapz, as suggested by Torsten.
I = trapz(x,y);
If you do not want to bother with x, and you know the (fixed) step between subsequent points, you can use
I = dx*trapz(y)

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeNumerical Integration and Differentiation についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by