cell to matrix

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ricco
ricco 2011 年 11 月 3 日
I have a data set which is in a cell structure (<1x20>) I want to place all of the data into one matrix. As each of the data sets in this cell structure is of different size, such as the first one is: 61169x15 and the second is 59529x15 and so on... i'm trying to find a way of combining the cells into a matrix. I can do this manually by:
new_data=[data1;data2;data3;data4]
But i would like to run the same script for other data sets therefore am looking for a way of doing this in a loop. Is that possible? So, I was thinking of a loop which ran though the cells i.e. for i=1:size(data,2) %=1:20
and then applying the same process as above in the loop, but im not sure on how I would go about doing this.
thanks
  1 件のコメント
Jan
Jan 2011 年 11 月 4 日
Please by careful with the term "structure". It is often confused with "STRUCT" array.

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採用された回答

Jan
Jan 2011 年 11 月 4 日
If all cell elements have teh same number of columns:
new_data = cat(1, data{:});
  3 件のコメント
ricco
ricco 2011 年 11 月 4 日
It works now, thank you very much for your help. The problem was that the data wasn't cleaned by who ever recovered it so one of the arrays had a different number of columns (14 not 15) due to an instrument malfunction. Which I probably wouldn't have spotted without your comment above.
thanks again

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その他の回答 (2 件)

Fangjun Jiang
Fangjun Jiang 2011 年 11 月 3 日
If all cells have the same number of columns, would this help?
a{1}=rand(3,2);
a{2}=rand(4,2);
a{3}=rand(5,2);
cell2mat(a')
  2 件のコメント
Jan
Jan 2011 年 11 月 4 日
@ricco: No, the type of the cell elements does not matter - btw.: Fangjun's data are DOUBLEs also. But the dimensions must be matching. While "cell2mat(a')" works, "cell2mat(a)" must fail.

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Ora Zyto
Ora Zyto 2011 年 11 月 3 日
From your description, it seems like all of your data sets have the same number of columns, and varying number of rows. In your for loop, append your current dataset to your existing matrix:
for i=1:length(data),
new_data=[new_data;data{i}]
end
Ora
  3 件のコメント
Ora Zyto
Ora Zyto 2011 年 11 月 4 日
@Jan Simon: You are totally right. I didn't think about the CAT function :-)

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