How to deduct obtained fuel value from initial weight

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Ke Yeun Yong
Ke Yeun Yong 2023 年 9 月 21 日
編集済み: Ke Yeun Yong 2023 年 9 月 21 日
Hi, the following code is the initial calculation, I have obtained the fuel consumed to climb at each altitude (53 x 1 results) (the final code), I want to deduct this fuel consumption from the weight at every altitude (the weight is denoted is W) because weight reduced as the aircraft fly.
May I know how do I code it? I heard can use for-loop with different iteration? (because I have used a for-loop for other calculation before getting onto the coding below)
Please help. Very much appreciate :)
%% Coefficient of Lift
CDO = 0.023; % Zero-lift drag coefficient
K = 0.044; % Lift-induced drag factor
MTOW = 79010; % Maximum take-off mass [kg]
W = MTOW*9.81; % Weight in N
A= Thrust_22K/W;
B = sqrt((A.^2)+(12*CDO*K));
Cl = (6*CDO)./(A+B);
%% Drag Produced
S = 125; % Wing area [m^2]
C = CDO + (K*(Cl.^2));
D = 0.5*Density_altitude.*(TAS.^2)*S.*C; % [N]
%% Power Available
P_available = TAS.*Thrust_22K;
%% Power Required
P_required = TAS.*D;
%% Excess Power
P_excess = P_available - P_required;
%% Rate of Climb (ROC)
ROC = (TAS.*(Thrust_22K - D))./W; % [m/s]
if any(ROC <=1.5)
disp('Service Ceiling.')
else
disp ('Absolute Ceiling.')
end
%% Climb Angle
X = (Thrust_22K - D)./W;
Climb_angle = asind( X ); % [Degree]
%% Time Taken to Climb
Time = Altitude./ROC; % [sec]
%% Mass Flow Rate
m_dot_f = TSFC_22K.*Thrust_22K; % [kg/s]
%% Fuel Consumed to Climb
Fuel = m_dot_f.*Time;
  5 件のコメント
William Rose
William Rose 2023 年 9 月 21 日
編集済み: William Rose 2023 年 9 月 21 日
As @Dyuman Joshi pointed out, it is not clear what quantities are vectors and what quatities are scalars.
Dyuman Joshi
Dyuman Joshi 2023 年 9 月 21 日
It will be better if you can attach your whole code including values for variables, as has been mentioned before.

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Torsten
Torsten 2023 年 9 月 21 日
編集済み: Torsten 2023 年 9 月 21 日
Most probably something like this. I don't know where you use some of the defined variables - they seem to be superfluous.
%% Coefficient of Lift
CDO = 0.023; % Zero-lift drag coefficient
K = 0.044; % Lift-induced drag factor
W(1) = MTOW*9.81; % Weight in N;
Time(1) = 0.0;
Fuel(1) = 0.0;
for i = 1:numel(Altitude)-1
A = Thrust_22K/W(i);
B = sqrt((A.^2)+(12*CDO*K));
Cl = (6*CDO)./(A+B);
%% Drag Produced
S = 125; % Wing area [m^2]
C = CDO + (K*(Cl.^2));
D = 0.5*(Density_altitude(i)+Density_altitude(i+1))/2.*(TAS.^2)*S.*C; % [N]
%% Power Available
P_available = TAS.*Thrust_22K;
%% Power Required
P_required = TAS.*D;
%% Excess Power
P_excess = P_available - P_required;
%% Rate of Climb (ROC)
ROC = (TAS.*(Thrust_22K - D))./W(i); % [m/s]
if any(ROC <=1.5)
disp('Service Ceiling.')
else
disp ('Absolute Ceiling.')
end
%% Climb Angle
X = (Thrust_22K - D)./W(i);
Climb_angle = asind( X ); % [Degree]
%% Time Taken to Climb
Time(i+1) = (Altitude(i+1)-Altitude(i))./ROC; % [sec]
%% Mass Flow Rate
m_dot_f = TSFC_22K.*Thrust_22K; % [kg/s]
%% Fuel Consumed to Climb
Fuel(i+1) = m_dot_f.*Time(i+1);
W(i+1) = W(i) - Fuel(i+1);
end
  6 件のコメント
Ke Yeun Yong
Ke Yeun Yong 2023 年 9 月 21 日
編集済み: Ke Yeun Yong 2023 年 9 月 21 日
I applied your coding and i got the following error in command window;
Unable to perform assignment because the left and right sides have a different number of elements.
Error in Copy_of_Calculation_22K (line 86)
Time(i+1) = (Altitude(i+1)-Altitude(i))./ROC; % [sec]
Furthermore, the time and fuel increases with altitude so i think i dont have to do sum for them. As the calculation shows the time and fuel at each altitude and not the difference between two altitude. Please correct me if I am wrong.
Thank you.
Torsten
Torsten 2023 年 9 月 21 日
編集済み: Torsten 2023 年 9 月 21 日
ROC = (TAS.*(Thrust_22K - D))./W(i); % [m/s]
Use the local value for all arrays that are part of this expression.
Maybe
ROC = TAS(i)*(Thrust_22K(i)-D)/W(i);
?
We don't know. You must use the local values (at Altitude(i+1)) everywhere where needed.

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