Simple Question: How to Plot a Function over an Interval (Details in Body)

Hello, it's been too long since I've used Matlab.

Could someone please help me with the following? I tried looking online but other solutions didn't help me for some reason. Thanks in advance!

t = 0:0.01:pi % Theta from 0 to pi

tm = sqrt(44*cos(t).^2 + 44*cos(t)*sin(t)+29*sin(t).^2)

plot(t, tm(t))

[Michael Meyne]

I've gotten one step closer but now with error:

t = 0:0.01:pi % Theta from 0 to pi

%

tm = sqrt(44.*cos(t).^2 + 44*cos(t).*sin(t)+29.*sin(t).^2) % traction magnitude eqn derived on paper

plot(t, tm(t))

Array indices must be positive integers or logical values.

Error in HW2_1a_SMI_Michael_Meyne (line 16)

plot(t, tm(t))

[Torsten]

t = 0:0.01:pi; % Theta from 0 to pi
% 
tm = sqrt(44*cos(t).^2 + 44*cos(t).*sin(t)+29*sin(t).^2); % traction magnitude eqn derived on paper
plot(t, tm)

[Michael Meyne]

Thank you Torsten!

Answer 1

[Sam Chak]

Hi @Michael Meyne

Alternatively, you can also use fplot() to symbolically plot the function over the specified interval for t.

See also: https://www.mathworks.com/help/matlab/ref/fplot.html

syms t
tm = @(t) sqrt(44*cos(t).^2 + 44*cos(t).*sin(t) + 29*sin(t).^2);
fplot(tm, [0 pi])

grid on
title('tm(t) from 0 to \pi')
xlabel('t');
ylabel('tm');