I’m thinking of make a command to change Hankel matrix into x time series
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y = [17 24 1 8 15 23 5 7 14 16 4 6 13 20 22 10 12 19 21 3 11 18 25 2 9] my question how could I use function to be x = [17 ,24,5,7,13,20,21,3,9].
1 件のコメント
Shantanu Dixit
2023 年 6 月 29 日
Could you please elaborate, it's a bit unclear what you're asking. Thanks
回答 (1 件)
David Goodmanson
2023 年 6 月 29 日
編集済み: David Goodmanson
2023 年 6 月 30 日
Hi Ahmed,
here is one way
y = magic(5)
n = size(y,2);
x = zeros(1,2*n-1);
x(1:2:end) = diag(y).';
x(2:2:end) = diag(y,1).'
2 件のコメント
David Goodmanson
2023 年 6 月 29 日
編集済み: David Goodmanson
2023 年 6 月 30 日
Hi Ahmed,
your example was a square matrix. I changed the code in the answer so it works when there are more rows than columns, such as 5000x3000. Except in that case, at row 3000 the pattern will hit column 3000 at the right hand side of the matrix. This leaves a 2000x3000 matrix at the bottom that is not being sampled from. Is anythng supposed to happen then?
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