accessing subplot grid title (sgtitle) from figure properties
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How to get the sgtitle of a figure directly from the properties?
For the fig title, this is fairly straightforward and ideal when wishing to save a large volume of open figures automatically:
titleName = gca(figObj).Title.String
However there is no obvious property name for subplot grid title (sgtitle) that can be readily accessed. Yet clearly the sgtitle information is retained after closing as it reappears upon reopening a figure. Is it just that this property is not accessible to users? This seems unlikely, especially given the many dozens of properties available.
Cheers.
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採用された回答
Star Strider
2023 年 6 月 14 日
The sgtitle object is a child of the figure. The problem is that it doesn’t appear straightforward to access using findobj.
x = [1;1]*(0:15);
y = randn(2, size(x,2));
figure
subplot(2,1,1)
plot(x(1,:), y(1,:))
xlabel('x_1')
ylabel('y_1')
title('Subplot #1')
subplot(2,1,2)
plot(x(2,:), y(2,:))
xlabel('x_2')
ylabel('y_2')
title('Subplot #2')
sgtitle('Subplots')
hf = gcf;
Kids = hf.Children
obj = findobj(gcf)
sgt = findobj(hf, 'Type','Text')
sgt = findobj(hf.Children, 'Type','Text')
sgt = Kids(1)
It’s definitely possible to get it, however its type appears not to correspond with what I’d normally expect. That appears to be some undocumented property.
.
その他の回答 (1 件)
Steven Lord
2023 年 6 月 14 日
The object created and returned by sgtitle has a Type that is not the same as its class.
x = [1;1]*(0:15);
y = randn(2, size(x,2));
figure
subplot(2,1,1)
plot(x(1,:), y(1,:))
xlabel('x_1')
ylabel('y_1')
title('Subplot #1')
subplot(2,1,2)
plot(x(2,:), y(2,:))
xlabel('x_2')
ylabel('y_2')
title('Subplot #2')
h = sgtitle('Subplots');
h.Type
hf = gcf;
sgt = findobj(hf, 'Type','subplottext')
sgt == h % true
Of course, even easier is to call sgtitle with an output argument and keep that variable around, as I did with the variable named h.
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