# How to flip an ordered X-axis that is half half separated for data?

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Dorna 2023 年 6 月 3 日

Hi, I have a plot that I want its X-axis to be reversed. My data on X-axis is showing as
[1 2 3 4 5 6 7 8 9 10 11 12] I want to reverse it in a way that it represents [6 5 4 3 2 1 12 11 10 9 8 7] (reversing it from the middle for two seperate parts). How is it possible? I tried set(gca, 'XDir','reverse') but it reverses it to [12 11 10 9 8 7 6 5 4 3 2 1]. I cannot share the code or data due to confidentiality. Thanks in advance.

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### 採用された回答

Dorna 2023 年 6 月 4 日
Ok, so what I needed to do was
A = Data((1:20),(1:5))
B = flip(A,1)
C = Data((21:40),(1:5))
D = flip(C,1)
And then
New = cat(1,B,D)
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Star Strider 2023 年 6 月 4 日

O.K.
That seems to be essentially what I wrote, although in one column not five. You can use my approach to plot it.

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### その他の回答 (2 件)

VBBV 2023 年 6 月 3 日
Use xticklabels function to modify the order of axis labels
x1 = {'6','5','4','3','2','1'};
x2 ={'12','11','10','9','8','7'};
plot(rand(1,12))
xticks(1:12)
xticklabels([x1,x2])
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Dorna 2023 年 6 月 3 日
@VBBV will also flip the data? I think it will only flip the axis label. Plus i prefer something that does not require me to actually work with the plots as they are very complex. Something like set gca
VBBV 2023 年 6 月 3 日

can you explain why you DONT want to actually work with plot data but still want to flip ordered x-axis values ?
v = [16 5 9 4 2 11 7 14];
v2 = v([5:8 1:4]) % Extract and swap the halves of v
v2 = 1×8
2 11 7 14 16 5 9 4
% flip the values for vector v
v2 = flip(v)
v2 = 1×8
14 7 11 2 4 9 5 16
% another way
v2 = v([8:-1:5 , 4:-1:1])
v2 = 1×8
14 7 11 2 4 9 5 16
How can I make the V2 to be [14 7 11 2 4 9 5 16], can I use prime on 5:8'?
You can use the flip function to get the desired result as shown above

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Star Strider 2023 年 6 月 3 日
One approach that changes the x-axis and the data —
xv = [1 2 3 4 5 6 7 8 9 10 11 12]; % Independent Variable
yv = (xv/max(xv)).^2; % Dependent Variable
xvi = [6 5 4 3 2 1 12 11 10 9 8 7]; % Indexing Vector
figure
plot(xv, yv)
grid
xticks(xv)
title('Original')
Vectors = [xv(xvi); yv(xvi)]
Vectors = 2×12
6.0000 5.0000 4.0000 3.0000 2.0000 1.0000 12.0000 11.0000 10.0000 9.0000 8.0000 7.0000 0.2500 0.1736 0.1111 0.0625 0.0278 0.0069 1.0000 0.8403 0.6944 0.5625 0.4444 0.3403
figure
plot(xv, yv(xvi))
grid
xticks(xv)
xticklabels(xv(xvi))
title('Reversed & Concatenated')
It may be challenging to elliminate the connecting line between 1 and 12 here. If necessary, that would require putting a NaN value at the beginning or end of the ‘xv’ and ‘yv’ vectors, and adjusting ‘xvi’ accordingly.
.
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Dorna 2023 年 6 月 4 日
@Star Strider thank you so much. I think what I needed was what I posted as answer but I do really appreciate your input.
Dorna 2023 年 6 月 4 日
I wish there was an easier alternative to the solution that I posted.

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