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Read notepad into a variable

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rockstar49
rockstar49 2023 年 5 月 25 日
回答済み: Image Analyst 2023 年 5 月 28 日
Hi,
Id like to read a notepad file row and make that into a variable
txt{6}(1:end-1)=File(cals,txt{6}(1:end-1)); (says Conversion to char from struct is not possible)
I can run this command: txt{6}(1:end-1) and it would give me, ans="x"
i can also run A=File(cals,txt{6}(1:end-1)); and it would output a 1 by 1 structure with a value inside it.
Any suggetions?
Do i need to use eval? etc
Thank you!
  7 件のコメント
Steven Lord
Steven Lord 2023 年 5 月 25 日
How did you create the variable named txt?
rockstar49
rockstar49 2023 年 5 月 26 日
I used importdata (notepad file)

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回答 (2 件)

Diwakar Diwakar
Diwakar Diwakar 2023 年 5 月 25 日
% Specify the path to the text file
filePath = 'path/to/your/file.txt';
% Read the text file
fileData = fileread(filePath);
% Split the file contents by newline character to get individual rows
rows = split(fileData, '\n');
% Select the desired row (in this example, row number 6)
rowIndex = 6;
selectedRow = rows{rowIndex};
% Display the selected row
disp(selectedRow);
% Store the selected row in a variable
myVariable = selectedRow;
You are trying to assign its value to the variable txt{6}(1:end-1) directly, which is causing the error. Try this code.
  8 件のコメント
Stephen23
Stephen23 2023 年 5 月 27 日
Just use READCELLS or READLINES or similar.
Walter Roberson
Walter Roberson 2023 年 5 月 27 日
An example extract from the file would help.
As would a clearer description of what you are trying to do with the information.

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Image Analyst
Image Analyst 2023 年 5 月 28 日
Try
textLines = readlines(fileName);
If you have any more questions, then attach your text file with the paperclip icon after you read this:

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